To determine which two swimmers swam at the same rate, we need to compute the rate of laps swum per minute for each swimmer. The rate can be calculated by dividing the number of laps by the time taken.
Let's calculate the rate for each swimmer:
1. Jonathan:
[tex]\[
\text{Rate} = \frac{\text{Laps}}{\text{Time}} = \frac{2}{4} = 0.5 \text{ laps per minute}
\][/tex]
2. Julian:
[tex]\[
\text{Rate} = \frac{\text{Laps}}{\text{Time}} = \frac{1}{1} = 1 \text{ lap per minute}
\][/tex]
3. Seth:
[tex]\[
\text{Rate} = \frac{\text{Laps}}{\text{Time}} = \frac{3}{6} = 0.5 \text{ laps per minute}
\][/tex]
4. Bennett:
[tex]\[
\text{Rate} = \frac{\text{Laps}}{\text{Time}} = \frac{7}{21} = \frac{1}{3} \text{ laps per minute} \approx 0.333 \text{ laps per minute}
\][/tex]
5. Taylor:
[tex]\[
\text{Rate} = \frac{\text{Laps}}{\text{Time}} = \frac{4}{7} \approx 0.571 \text{ laps per minute}
\][/tex]
After calculating the rates, we compare them to find which two swimmers have the same rate:
- Jonathan: 0.5 laps per minute
- Julian: 1 lap per minute
- Seth: 0.5 laps per minute
- Bennett: ~0.333 laps per minute
- Taylor: ~0.571 laps per minute
We observe that Jonathan and Seth both have a rate of 0.5 laps per minute.
Therefore, the correct answer is:
D. Jonathan and Seth
