Frosty0110idn
Answered

Get personalized answers to your unique questions on IDNLearn.com. Our Q&A platform is designed to provide quick and accurate answers to any questions you may have.

Match the salt with the acid and base used to form it in a neutralizing reaction.

A. [tex] K_2SO_4 [/tex]
1. KOH and [tex] H_2SO_4 [/tex]

B. NaBr
1. NaOH and HBr

C. [tex] H_3PO_4 [/tex] and NaOH
1. NaOH and HBr

D. [tex] HPO_4 [/tex] and KOH
1. KOH and [tex] H_2SO_4 [/tex]

E. NaCl and [tex] HSO_4 [/tex]
1. NaOH and HBr

Sagot :

GinnyAnsweridn
Certainly! Let's go through matching the salts with their respective acids and bases used to form them in a neutralization reaction.

1. [tex]\( K_2SO_4 \)[/tex] (Potassium Sulfate)
- To form potassium sulfate ([tex]\( K_2SO_4 \)[/tex]), you need a strong base and a strong acid.
- The correct acid-base pair here is: KOH (Potassium Hydroxide) and [tex]\( H_2SO_4 \)[/tex] (Sulfuric Acid)
- Neutralization reaction:
[tex]\[ 2 KOH + H_2SO_4 \rightarrow K_2SO_4 + 2 H_2O \][/tex]

2. NaBr (Sodium Bromide)
- To form sodium bromide ([tex]\( NaBr \)[/tex]), the necessary sodium base and bromide acid are:
- The correct acid-base pair here is: NaOH (Sodium Hydroxide) and HBr (Hydrobromic Acid)
- Neutralization reaction:
[tex]\[ NaOH + HBr \rightarrow NaBr + H_2O \][/tex]

So, the correct matches are:

1. Potassium Sulfate ([tex]\( K_2SO_4 \)[/tex]) is formed by:
- KOH and [tex]\( H_2SO_4 \)[/tex]

2. Sodium Bromide (NaBr) is formed by:
- NaOH and HBr
We appreciate your participation in this forum. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. Your search for solutions ends at IDNLearn.com. Thank you for visiting, and we look forward to helping you again.