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Solve for [tex]\( x \)[/tex] to make [tex]\( A \parallel B \)[/tex].

Given:
[tex]\[
3x + 20
\][/tex]

Find [tex]\( x \)[/tex].


Sagot :

To solve for [tex]\( x \)[/tex] so that [tex]\( A \parallel B \)[/tex], we need to understand that parallel lines have the same slope.

Let's go through this step-by-step:

1. Identify the equations:
- The equation for line [tex]\( A \)[/tex] is given as [tex]\( 3x + 20 \)[/tex].

2. Equation for line [tex]\( B \)[/tex]:
- Since we need line [tex]\( B \)[/tex] to be parallel to line [tex]\( A \)[/tex], and parallel lines have the same slope, the general form for line [tex]\( B \)[/tex] would also have the same slope as line [tex]\( A \)[/tex], but possibly a different y-intercept. Thus, if we denote the line [tex]\( B \)[/tex] in the form [tex]\( 3x + k \)[/tex].

3. Setting up the equation:
- To solve for [tex]\( x \)[/tex], we need to set the equation of [tex]\( A \)[/tex] equal to the equation of [tex]\( B \)[/tex]. Since both lines are parallel, their equations would intersect when they are set equal to each other:
[tex]\[ 3x + 20 = 3x + k \][/tex]

4. Solving for [tex]\( x \)[/tex]:
- Simplifying the equation [tex]\( 3x + 20 = 3x + k \)[/tex]:
[tex]\[ \begin{align*} 3x + 20 &= 3x + k \\ 20 &= k \end{align*} \][/tex]
- The above equation holds true regardless of [tex]\( x \)[/tex]. To find a specific value for [tex]\( x \)[/tex], we rearrange the equation:
[tex]\[ 3x = k - 20 \][/tex]
[tex]\[ x = \frac{k - 20}{3} \][/tex]

Therefore, the value of [tex]\( x \)[/tex] that makes lines [tex]\( A \)[/tex] and [tex]\( B \)[/tex] parallel is:
[tex]\[ x = \frac{k}{3} - \frac{20}{3}. \][/tex]
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