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Amira has [tex]$\frac{3}{4}$[/tex] of a bag of cat food. Her cat eats [tex]$\frac{1}{10}$[/tex] of a bag per week. How many weeks will the food last?

Sagot :

Sure, let's solve this problem step-by-step.

1. Identify the given values:
- Amira has [tex]\(\frac{3}{4}\)[/tex] of a bag of cat food.
- The cat eats [tex]\(\frac{1}{10}\)[/tex] of a bag each week.

2. Understand the question:
- We need to find out how many weeks the food will last.

3. Set up the problem:
- We start with [tex]\(\frac{3}{4}\)[/tex] of a bag.
- Each week, the cat consumes [tex]\(\frac{1}{10}\)[/tex] of a bag.

4. Calculate the number of weeks the food will last:
- To find how many weeks the food will last, we need to divide the total amount of food by the weekly consumption.
- This can be represented mathematically as:
[tex]\[ \text{Number of weeks} = \frac{\text{Total amount of food}}{\text{Weekly consumption}} \][/tex]

5. Substitute the given values into the formula:
- Total amount of food: [tex]\(\frac{3}{4}\)[/tex] of a bag.
- Weekly consumption: [tex]\(\frac{1}{10}\)[/tex] of a bag.
[tex]\[ \text{Number of weeks} = \frac{\frac{3}{4}}{\frac{1}{10}} \][/tex]

6. Performing the division:
- To divide by a fraction, multiply by its reciprocal. Thus,
[tex]\[ \frac{\frac{3}{4}}{\frac{1}{10}} = \frac{3}{4} \times \frac{10}{1} = \frac{3 \times 10}{4 \times 1} = \frac{30}{4} \][/tex]

7. Simplify the fraction:
- [tex]\(\frac{30}{4}\)[/tex] can be simplified by dividing both the numerator and the denominator by their greatest common divisor, which is 2:
[tex]\[ \frac{30}{4} = \frac{30 \div 2}{4 \div 2} = \frac{15}{2} \][/tex]
- [tex]\(\frac{15}{2}\)[/tex] is equal to 7.5 when expressed as a decimal.

8. Conclusion:
- The food will last for 7.5 weeks.

Thus, Amira's cat food will last for 7.5 weeks.