Discover a world of knowledge and community-driven answers at IDNLearn.com today. Get accurate and comprehensive answers to your questions from our community of knowledgeable professionals.
Sagot :
To determine which ordered pairs satisfy the given system of inequalities, we will evaluate each pair by substituting [tex]\( x = 6 \)[/tex] into the inequalities and check the corresponding [tex]\( y \)[/tex]-values.
The system of inequalities is:
[tex]\[ \begin{array}{l} y \leq \frac{2}{3} x + 1 \\ y > -\frac{1}{4} x + 2 \end{array} \][/tex]
First, let's substitute [tex]\( x = 6 \)[/tex] into the inequalities to simplify them:
1. For the first inequality, [tex]\( y \leq \frac{2}{3} x + 1 \)[/tex]:
[tex]\[ y \leq \frac{2}{3} \cdot 6 + 1 = 4 + 1 = 5 \][/tex]
2. For the second inequality, [tex]\( y > -\frac{1}{4} x + 2 \)[/tex]:
[tex]\[ y > -\frac{1}{4} \cdot 6 + 2 = -1.5 + 2 = 0.5 \][/tex]
So, the simplified system of inequalities when [tex]\( x = 6 \)[/tex] is:
[tex]\[ \begin{array}{l} y \leq 5 \\ y > 0.5 \end{array} \][/tex]
Now, let's evaluate each ordered pair to see if they satisfy both conditions.
1. For the ordered pair [tex]\( (6, -2) \)[/tex]:
- Check the first inequality: [tex]\( -2 \leq 5 \)[/tex] (True)
- Check the second inequality: [tex]\( -2 > 0.5 \)[/tex] (False)
- Since one of the inequalities is false, [tex]\( (6, -2) \)[/tex] is not a solution.
2. For the ordered pair [tex]\( (6, 0.5) \)[/tex]:
- Check the first inequality: [tex]\( 0.5 \leq 5 \)[/tex] (True)
- Check the second inequality: [tex]\( 0.5 > 0.5 \)[/tex] (False)
- Since one of the inequalities is false, [tex]\( (6, 0.5) \)[/tex] is not a solution.
3. For the ordered pair [tex]\( (6, 5) \)[/tex]:
- Check the first inequality: [tex]\( 5 \leq 5 \)[/tex] (True)
- Check the second inequality: [tex]\( 5 > 0.5 \)[/tex] (True)
- Since both inequalities are true, [tex]\( (6, 5) \)[/tex] is a solution.
4. For the ordered pair [tex]\( (6, 8) \)[/tex]:
- Check the first inequality: [tex]\( 8 \leq 5 \)[/tex] (False)
- Check the second inequality: [tex]\( 8 > 0.5 \)[/tex] (True)
- Since one of the inequalities is false, [tex]\( (6, 8) \)[/tex] is not a solution.
The ordered pair that satisfies both inequalities in the system is [tex]\( (6, 5) \)[/tex].
The system of inequalities is:
[tex]\[ \begin{array}{l} y \leq \frac{2}{3} x + 1 \\ y > -\frac{1}{4} x + 2 \end{array} \][/tex]
First, let's substitute [tex]\( x = 6 \)[/tex] into the inequalities to simplify them:
1. For the first inequality, [tex]\( y \leq \frac{2}{3} x + 1 \)[/tex]:
[tex]\[ y \leq \frac{2}{3} \cdot 6 + 1 = 4 + 1 = 5 \][/tex]
2. For the second inequality, [tex]\( y > -\frac{1}{4} x + 2 \)[/tex]:
[tex]\[ y > -\frac{1}{4} \cdot 6 + 2 = -1.5 + 2 = 0.5 \][/tex]
So, the simplified system of inequalities when [tex]\( x = 6 \)[/tex] is:
[tex]\[ \begin{array}{l} y \leq 5 \\ y > 0.5 \end{array} \][/tex]
Now, let's evaluate each ordered pair to see if they satisfy both conditions.
1. For the ordered pair [tex]\( (6, -2) \)[/tex]:
- Check the first inequality: [tex]\( -2 \leq 5 \)[/tex] (True)
- Check the second inequality: [tex]\( -2 > 0.5 \)[/tex] (False)
- Since one of the inequalities is false, [tex]\( (6, -2) \)[/tex] is not a solution.
2. For the ordered pair [tex]\( (6, 0.5) \)[/tex]:
- Check the first inequality: [tex]\( 0.5 \leq 5 \)[/tex] (True)
- Check the second inequality: [tex]\( 0.5 > 0.5 \)[/tex] (False)
- Since one of the inequalities is false, [tex]\( (6, 0.5) \)[/tex] is not a solution.
3. For the ordered pair [tex]\( (6, 5) \)[/tex]:
- Check the first inequality: [tex]\( 5 \leq 5 \)[/tex] (True)
- Check the second inequality: [tex]\( 5 > 0.5 \)[/tex] (True)
- Since both inequalities are true, [tex]\( (6, 5) \)[/tex] is a solution.
4. For the ordered pair [tex]\( (6, 8) \)[/tex]:
- Check the first inequality: [tex]\( 8 \leq 5 \)[/tex] (False)
- Check the second inequality: [tex]\( 8 > 0.5 \)[/tex] (True)
- Since one of the inequalities is false, [tex]\( (6, 8) \)[/tex] is not a solution.
The ordered pair that satisfies both inequalities in the system is [tex]\( (6, 5) \)[/tex].
We appreciate every question and answer you provide. Keep engaging and finding the best solutions. This community is the perfect place to learn and grow together. Thank you for choosing IDNLearn.com. We’re here to provide reliable answers, so please visit us again for more solutions.