Get detailed and reliable answers to your questions with IDNLearn.com. Discover reliable and timely information on any topic from our network of experienced professionals.
Sagot :
To simplify the expression [tex]\(\frac{\tan 9x - \tan 5x}{1 + \tan 9x \tan 5x}\)[/tex], we will use a known tangent subtraction formula.
The tangent subtraction formula states:
[tex]\[ \tan(A - B) = \frac{\tan A - \tan B}{1 + \tan A \tan B} \][/tex]
In our given problem, we can identify [tex]\(A\)[/tex] and [tex]\(B\)[/tex] as follows:
- [tex]\(A = 9x\)[/tex]
- [tex]\(B = 5x\)[/tex]
Using the tangent subtraction formula:
[tex]\[ \tan(9x - 5x) = \frac{\tan 9x - \tan 5x}{1 + \tan 9x \tan 5x} \][/tex]
Simplifying the right-hand side:
[tex]\[ \tan(9x - 5x) = \frac{\tan 9x - \tan 5x}{1 + \tan 9x \tan 5x} \][/tex]
We know:
[tex]\[ 9x - 5x = 4x \][/tex]
Therefore:
[tex]\[ \tan(4x) = \frac{\tan 9x - \tan 5x}{1 + \tan 9x \tan 5x} \][/tex]
Thus, the expression [tex]\(\frac{\tan 9x - \tan 5x}{1 + \tan 9x \tan 5x}\)[/tex] simplifies to:
[tex]\[ \tan(4x) \][/tex]
So, the simplified form of the given expression is:
[tex]\[ \tan(4x) \][/tex]
The tangent subtraction formula states:
[tex]\[ \tan(A - B) = \frac{\tan A - \tan B}{1 + \tan A \tan B} \][/tex]
In our given problem, we can identify [tex]\(A\)[/tex] and [tex]\(B\)[/tex] as follows:
- [tex]\(A = 9x\)[/tex]
- [tex]\(B = 5x\)[/tex]
Using the tangent subtraction formula:
[tex]\[ \tan(9x - 5x) = \frac{\tan 9x - \tan 5x}{1 + \tan 9x \tan 5x} \][/tex]
Simplifying the right-hand side:
[tex]\[ \tan(9x - 5x) = \frac{\tan 9x - \tan 5x}{1 + \tan 9x \tan 5x} \][/tex]
We know:
[tex]\[ 9x - 5x = 4x \][/tex]
Therefore:
[tex]\[ \tan(4x) = \frac{\tan 9x - \tan 5x}{1 + \tan 9x \tan 5x} \][/tex]
Thus, the expression [tex]\(\frac{\tan 9x - \tan 5x}{1 + \tan 9x \tan 5x}\)[/tex] simplifies to:
[tex]\[ \tan(4x) \][/tex]
So, the simplified form of the given expression is:
[tex]\[ \tan(4x) \][/tex]
Thank you for joining our conversation. Don't hesitate to return anytime to find answers to your questions. Let's continue sharing knowledge and experiences! Discover insightful answers at IDNLearn.com. We appreciate your visit and look forward to assisting you again.