IDNLearn.com connects you with a community of experts ready to answer your questions. Our Q&A platform is designed to provide quick and accurate answers to any questions you may have.
Sagot :
To find the cube root of [tex]\(0.125\)[/tex], we denote it as [tex]\(\sqrt[3]{0.125}\)[/tex]. We are essentially looking for a number that, when multiplied by itself three times (cubed), equals [tex]\(0.125\)[/tex].
In other words, we need to solve for [tex]\(x\)[/tex] in the equation:
[tex]\[ x^3 = 0.125 \][/tex]
To begin, let's recall that [tex]\(0.125\)[/tex] can be expressed as a fraction:
[tex]\[ 0.125 = \frac{125}{1000} = \frac{1}{8} \][/tex]
Now, we need to find the cube root of [tex]\(\frac{1}{8}\)[/tex]:
[tex]\[ x = \sqrt[3]{\frac{1}{8}} \][/tex]
We know that:
[tex]\[ \left(\frac{1}{2}\right)^3 = \frac{1^3}{2^3} = \frac{1}{8} \][/tex]
Thus:
[tex]\[ \sqrt[3]{\frac{1}{8}} = \frac{1}{2} \][/tex]
So, the cube root of [tex]\(\frac{1}{8}\)[/tex] is [tex]\(\frac{1}{2}\)[/tex], which is the same as [tex]\(0.5\)[/tex].
Therefore, the cube root of [tex]\(0.125\)[/tex] is:
[tex]\[ \sqrt[3]{0.125} = 0.5 \][/tex]
In other words, we need to solve for [tex]\(x\)[/tex] in the equation:
[tex]\[ x^3 = 0.125 \][/tex]
To begin, let's recall that [tex]\(0.125\)[/tex] can be expressed as a fraction:
[tex]\[ 0.125 = \frac{125}{1000} = \frac{1}{8} \][/tex]
Now, we need to find the cube root of [tex]\(\frac{1}{8}\)[/tex]:
[tex]\[ x = \sqrt[3]{\frac{1}{8}} \][/tex]
We know that:
[tex]\[ \left(\frac{1}{2}\right)^3 = \frac{1^3}{2^3} = \frac{1}{8} \][/tex]
Thus:
[tex]\[ \sqrt[3]{\frac{1}{8}} = \frac{1}{2} \][/tex]
So, the cube root of [tex]\(\frac{1}{8}\)[/tex] is [tex]\(\frac{1}{2}\)[/tex], which is the same as [tex]\(0.5\)[/tex].
Therefore, the cube root of [tex]\(0.125\)[/tex] is:
[tex]\[ \sqrt[3]{0.125} = 0.5 \][/tex]
Thank you for using this platform to share and learn. Keep asking and answering. We appreciate every contribution you make. Discover insightful answers at IDNLearn.com. We appreciate your visit and look forward to assisting you again.