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Sagot :
Of course! To determine the electric field between two plates separated by a specific distance given a potential difference, we can use the formula:
[tex]\[ E = \frac{V}{d} \][/tex]
where:
- [tex]\( E \)[/tex] is the electric field (in Newtons per Coulomb, N/C),
- [tex]\( V \)[/tex] is the potential difference (in Volts, V),
- [tex]\( d \)[/tex] is the separation between the plates (in meters, m).
Given the values:
- The potential difference [tex]\( V \)[/tex] is 20.0 V,
- The distance [tex]\( d \)[/tex] between the plates is 0.00500 m.
We substitute these values into the formula:
[tex]\[ E = \frac{20.0 \text{ V}}{0.00500 \text{ m}} \][/tex]
Now performing the division:
[tex]\[ E = \frac{20.0}{0.00500} \][/tex]
[tex]\[ E = 4000 \text{ N/C} \][/tex]
Therefore, the electric field between the plates is [tex]\( 4000 \text{ N/C} \)[/tex].
[tex]\[ E = \frac{V}{d} \][/tex]
where:
- [tex]\( E \)[/tex] is the electric field (in Newtons per Coulomb, N/C),
- [tex]\( V \)[/tex] is the potential difference (in Volts, V),
- [tex]\( d \)[/tex] is the separation between the plates (in meters, m).
Given the values:
- The potential difference [tex]\( V \)[/tex] is 20.0 V,
- The distance [tex]\( d \)[/tex] between the plates is 0.00500 m.
We substitute these values into the formula:
[tex]\[ E = \frac{20.0 \text{ V}}{0.00500 \text{ m}} \][/tex]
Now performing the division:
[tex]\[ E = \frac{20.0}{0.00500} \][/tex]
[tex]\[ E = 4000 \text{ N/C} \][/tex]
Therefore, the electric field between the plates is [tex]\( 4000 \text{ N/C} \)[/tex].
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