To determine the sum of the forces acting on an object using Newton's Second Law of Motion, we use the formula:
[tex]\[ F = m \cdot a \][/tex]
where:
- [tex]\( F \)[/tex] is the force in Newtons ([tex]\( N \)[/tex]),
- [tex]\( m \)[/tex] is the mass in kilograms ([tex]\( kg \)[/tex]),
- [tex]\( a \)[/tex] is the acceleration in meters per second squared ([tex]\( m/s^2 \)[/tex]).
Given:
- The mass of the object is 80 grams.
- The acceleration is 20 meters per second squared.
First, we must convert the mass from grams to kilograms because the standard unit of mass in the International System of Units (SI) is the kilogram.
[tex]\[ 80 \, \text{grams} = 80 \times \frac{1}{1000} = 0.08 \, \text{kg} \][/tex]
Next, we use the given acceleration:
[tex]\[ a = 20 \, \text{m/s}^2 \][/tex]
Now, we can substitute the values into the formula:
[tex]\[ F = m \cdot a = 0.08 \, \text{kg} \times 20 \, \text{m/s}^2 \][/tex]
[tex]\[ F = 1.6 \, \text{N} \][/tex]
Hence, the calculation of the sum of the forces acting on the object is as follows:
Given the options:
(A) [tex]\( 80 \cdot 20 \)[/tex]
(B) [tex]\( 8 ก .10 \cap ก .2 \cap \)[/tex]
Option (A) [tex]\( 80 \cdot 20 \)[/tex] is a possible representation if the original units (grams and meters per second squared) are used. Notice that when considering grams as 80 and acceleration as 20, without conversion to standard units, the value 1600 can be connected to non-standard representation which would later convert as:
[tex]\[ 80 \, \text{grams} \times 20 \, \text{m/s}^2 = (0.08 \, \text{kg} \times 1000) \times 20 = 1.6 \, \text{N} \times 1000 \][/tex]
But representation must consist of standard SI units only. So selecting and clarifying Option (A) [tex]\( 80 \cdot 20 \)[/tex] base highlight simplified original form.
Therefore, the correct choice is:
(A) [tex]\( 80 \cdot 20 \)[/tex]
