IDNLearn.com is the place where your questions are met with thoughtful and precise answers. Get step-by-step guidance for all your technical questions from our knowledgeable community members.
Sagot :
To find [tex]\( f(B) \)[/tex] where [tex]\( f(x) = x^2 - 4x + 3 \)[/tex], we'll plug the matrix [tex]\( B \)[/tex] into the function. Let's go through the steps:
1. Define the Matrix [tex]\( B \)[/tex]:
[tex]\[ B = \begin{bmatrix} 1 & 2 & 0 \\ 3 & -4 & 5 \\ 0 & -1 & 2 \end{bmatrix} \][/tex]
2. Calculate [tex]\( B^2 \)[/tex]:
To calculate [tex]\( B^2 \)[/tex], we multiply [tex]\( B \)[/tex] by itself:
[tex]\[ B \cdot B = \begin{bmatrix} 1 & 2 & 0 \\ 3 & -4 & 5 \\ 0 & -1 & 2 \end{bmatrix} \cdot \begin{bmatrix} 1 & 2 & 0 \\ 3 & -4 & 5 \\ 0 & -1 & 2 \end{bmatrix} = \begin{bmatrix} 7 & -6 & 10 \\ -9 & 17 & -10 \\ -3 & 2 & -1 \end{bmatrix} \][/tex]
3. Calculate [tex]\( 4B \)[/tex]:
Multiply [tex]\( B \)[/tex] by 4:
[tex]\[ 4B = 4 \times \begin{bmatrix} 1 & 2 & 0 \\ 3 & -4 & 5 \\ 0 & -1 & 2 \end{bmatrix} = \begin{bmatrix} 4 & 8 & 0 \\ 12 & -16 & 20 \\ 0 & -4 & 8 \end{bmatrix} \][/tex]
4. Calculate [tex]\( 3I \)[/tex]:
Multiply the 3x3 identity matrix [tex]\( I \)[/tex] by 3:
[tex]\[ 3I = 3 \times \begin{bmatrix} 1 & 0 & 0 \\ 0 & 1 & 0 \\ 0 & 0 & 1 \end{bmatrix} = \begin{bmatrix} 3 & 0 & 0 \\ 0 & 3 & 0 \\ 0 & 0 & 3 \end{bmatrix} \][/tex]
5. Combine the Results to Find [tex]\( f(B) \)[/tex]:
Using the function [tex]\( f(x) = x^2 - 4x + 3 \)[/tex], we substitute the matrix [tex]\( B \)[/tex]:
[tex]\[ f(B) = B^2 - 4B + 3I \][/tex]
Substitute the matrices we calculated:
[tex]\[ f(B) = \begin{bmatrix} 7 & -6 & 10 \\ -9 & 17 & -10 \\ -3 & 2 & -1 \end{bmatrix} - \begin{bmatrix} 4 & 8 & 0 \\ 12 & -16 & 20 \\ 0 & -4 & 8 \end{bmatrix} + \begin{bmatrix} 3 & 0 & 0 \\ 0 & 3 & 0 \\ 0 & 0 & 3 \end{bmatrix} \][/tex]
Perform the matrix subtraction and addition:
[tex]\[ f(B) = \begin{bmatrix} 7 - 4 + 3 & -6 - 8 + 0 & 10 - 0 + 0 \\ -9 - 12 + 0 & 17 - (-16) + 3 & -10 - 20 + 0 \\ -3 - 0 + 0 & 2 - (-4) + 0 & -1 - 8 + 3 \end{bmatrix} = \begin{bmatrix} 6 & -14 & 10 \\ -21 & 36 & -30 \\ -3 & 6 & -6 \end{bmatrix} \][/tex]
Thus, the final result for [tex]\( f(B) \)[/tex] is:
[tex]\[ f(B) = \begin{bmatrix} 6 & -14 & 10 \\ -21 & 36 & -30 \\ -3 & 6 & -6 \end{bmatrix} \][/tex]
1. Define the Matrix [tex]\( B \)[/tex]:
[tex]\[ B = \begin{bmatrix} 1 & 2 & 0 \\ 3 & -4 & 5 \\ 0 & -1 & 2 \end{bmatrix} \][/tex]
2. Calculate [tex]\( B^2 \)[/tex]:
To calculate [tex]\( B^2 \)[/tex], we multiply [tex]\( B \)[/tex] by itself:
[tex]\[ B \cdot B = \begin{bmatrix} 1 & 2 & 0 \\ 3 & -4 & 5 \\ 0 & -1 & 2 \end{bmatrix} \cdot \begin{bmatrix} 1 & 2 & 0 \\ 3 & -4 & 5 \\ 0 & -1 & 2 \end{bmatrix} = \begin{bmatrix} 7 & -6 & 10 \\ -9 & 17 & -10 \\ -3 & 2 & -1 \end{bmatrix} \][/tex]
3. Calculate [tex]\( 4B \)[/tex]:
Multiply [tex]\( B \)[/tex] by 4:
[tex]\[ 4B = 4 \times \begin{bmatrix} 1 & 2 & 0 \\ 3 & -4 & 5 \\ 0 & -1 & 2 \end{bmatrix} = \begin{bmatrix} 4 & 8 & 0 \\ 12 & -16 & 20 \\ 0 & -4 & 8 \end{bmatrix} \][/tex]
4. Calculate [tex]\( 3I \)[/tex]:
Multiply the 3x3 identity matrix [tex]\( I \)[/tex] by 3:
[tex]\[ 3I = 3 \times \begin{bmatrix} 1 & 0 & 0 \\ 0 & 1 & 0 \\ 0 & 0 & 1 \end{bmatrix} = \begin{bmatrix} 3 & 0 & 0 \\ 0 & 3 & 0 \\ 0 & 0 & 3 \end{bmatrix} \][/tex]
5. Combine the Results to Find [tex]\( f(B) \)[/tex]:
Using the function [tex]\( f(x) = x^2 - 4x + 3 \)[/tex], we substitute the matrix [tex]\( B \)[/tex]:
[tex]\[ f(B) = B^2 - 4B + 3I \][/tex]
Substitute the matrices we calculated:
[tex]\[ f(B) = \begin{bmatrix} 7 & -6 & 10 \\ -9 & 17 & -10 \\ -3 & 2 & -1 \end{bmatrix} - \begin{bmatrix} 4 & 8 & 0 \\ 12 & -16 & 20 \\ 0 & -4 & 8 \end{bmatrix} + \begin{bmatrix} 3 & 0 & 0 \\ 0 & 3 & 0 \\ 0 & 0 & 3 \end{bmatrix} \][/tex]
Perform the matrix subtraction and addition:
[tex]\[ f(B) = \begin{bmatrix} 7 - 4 + 3 & -6 - 8 + 0 & 10 - 0 + 0 \\ -9 - 12 + 0 & 17 - (-16) + 3 & -10 - 20 + 0 \\ -3 - 0 + 0 & 2 - (-4) + 0 & -1 - 8 + 3 \end{bmatrix} = \begin{bmatrix} 6 & -14 & 10 \\ -21 & 36 & -30 \\ -3 & 6 & -6 \end{bmatrix} \][/tex]
Thus, the final result for [tex]\( f(B) \)[/tex] is:
[tex]\[ f(B) = \begin{bmatrix} 6 & -14 & 10 \\ -21 & 36 & -30 \\ -3 & 6 & -6 \end{bmatrix} \][/tex]
Thank you for using this platform to share and learn. Don't hesitate to keep asking and answering. We value every contribution you make. For trustworthy answers, visit IDNLearn.com. Thank you for your visit, and see you next time for more reliable solutions.