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Sagot :
Certainly! Let's solve the problem step-by-step using the given trend line equation.
### Problem:
We are given the equation of the trend line for the cost of rideshare service:
[tex]\[ y = 2x + 6 \][/tex]
where:
- [tex]\( y \)[/tex] is the cost of the rideshare service in dollars.
- [tex]\( x \)[/tex] is the number of miles driven.
We need to predict the cost of the rideshare service for 10 miles.
### Steps to Solve:
1. Identify the given values:
- The number of miles driven ([tex]\( x \)[/tex]) is 10.
2. Substitute the given number of miles into the equation:
- The equation of the trend line is [tex]\( y = 2x + 6 \)[/tex].
- Substitute [tex]\( x = 10 \)[/tex] into the equation.
3. Perform the calculations:
[tex]\[ y = 2(10) + 6 \][/tex]
- First, multiply 2 by 10:
[tex]\[ 2 \times 10 = 20 \][/tex]
- Then, add 6 to the result:
[tex]\[ 20 + 6 = 26 \][/tex]
### Conclusion:
The cost of the rideshare service for driving 10 miles is:
[tex]\[ \mathbf{\$26} \][/tex]
So, the predicted cost of the rideshare service for 10 miles, based on the given trend line equation, is $26.
### Problem:
We are given the equation of the trend line for the cost of rideshare service:
[tex]\[ y = 2x + 6 \][/tex]
where:
- [tex]\( y \)[/tex] is the cost of the rideshare service in dollars.
- [tex]\( x \)[/tex] is the number of miles driven.
We need to predict the cost of the rideshare service for 10 miles.
### Steps to Solve:
1. Identify the given values:
- The number of miles driven ([tex]\( x \)[/tex]) is 10.
2. Substitute the given number of miles into the equation:
- The equation of the trend line is [tex]\( y = 2x + 6 \)[/tex].
- Substitute [tex]\( x = 10 \)[/tex] into the equation.
3. Perform the calculations:
[tex]\[ y = 2(10) + 6 \][/tex]
- First, multiply 2 by 10:
[tex]\[ 2 \times 10 = 20 \][/tex]
- Then, add 6 to the result:
[tex]\[ 20 + 6 = 26 \][/tex]
### Conclusion:
The cost of the rideshare service for driving 10 miles is:
[tex]\[ \mathbf{\$26} \][/tex]
So, the predicted cost of the rideshare service for 10 miles, based on the given trend line equation, is $26.
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