IDNLearn.com: Where your questions meet expert answers and community support. Discover in-depth answers to your questions from our community of experienced professionals.
Sagot :
Let's analyze the given synthetic division and use it to determine which statements are true.
We start by writing the polynomial and using synthetic division to find if the number 2 is a root of the polynomial [tex]\(F(x) = 3x^2 - 11x + 10\)[/tex].
The synthetic division process is shown below:
[tex]\[2 \ \left|\begin{array}{ccc} 3 & -11 & 10 \\ & 6 & -10 \\ \hline 3 & -5 & 0 \\ \end{array}\right.\][/tex]
Here's how it works step-by-step:
1. Write down the coefficients of the polynomial [tex]\(F(x)\)[/tex], which are [tex]\(3, -11, 10\)[/tex].
2. Place the 2 to the left (this is our test root).
3. Bring down the first coefficient (3) directly.
4. Multiply 2 by the value just written below the line (3), giving [tex]\(2 \times 3 = 6\)[/tex]. Write this under the second coefficient (-11).
5. Add the values in the second column [tex]\((-11 + 6 = -5)\)[/tex].
6. Multiply 2 by the value just written below the line (-5), giving [tex]\(2 \times -5 = -10\)[/tex]. Write this under the third coefficient (10).
7. Add the values in the third column [tex]\((10 + -10 = 0)\)[/tex].
After performing the synthetic division, we end up with:
[tex]\[2 \ \left|\begin{array}{ccc} 3 & -11 & 10 \\ & 6 & -10 \\ \hline 3 & -5 & 0 \\ \end{array}\right.\][/tex]
So, the division results in coefficients for a new polynomial (3x - 5) and a remainder of 0.
From this, we can deduce the following:
- Since the remainder is 0, 2 is indeed a root of [tex]\(F(x) = 3x^2 - 11x + 10\)[/tex].
- Because 2 is a root, [tex]\((x - 2)\)[/tex] is a factor of [tex]\(F(x)\)[/tex].
- The quotient polynomial obtained from the synthetic division is [tex]\(3x - 5\)[/tex].
Now let's evaluate each of the given statements:
A. The number -2 is a root of [tex]\(F(x) = 3x^2 - 11x + 10\)[/tex]. → False. The root is 2, not -2.
B. The number 2 is a root of [tex]\(F(x) = 3x^2 - 11x + 10\)[/tex]. → True.
C. [tex]\((x - 2)\)[/tex] is a factor of [tex]\(3x^2 - 11x + 10\)[/tex]. → True.
D. [tex]\(\left(3x^2 - 11x + 10\right) \div (x-2) = 3x - 5.\)[/tex] → True.
E. [tex]\((x + 2)\)[/tex] is a factor of [tex]\(3x^2 - 11x + 10\)[/tex]. → False. Only [tex]\((x - 2)\)[/tex] is a factor.
F. [tex]\(\left(3x^2 - 11x + 10\right) \div (x + 2) = 3x - 5\)[/tex]. → False, since [tex]\((x + 2)\)[/tex] is not a factor.
Thus, the correct statements are:
B. The number 2 is a root of [tex]\(F(x) = 3x^2 - 11x + 10\)[/tex].
C. [tex]\((x - 2)\)[/tex] is a factor of [tex]\(3x^2 - 11x + 10\)[/tex].
D. [tex]\(\left(3x^2 - 11x + 10\right) \div (x-2) = 3x - 5\)[/tex].
Therefore, the indices of the true statements are:
[tex]\[ [2, 3, 4] \][/tex]
We start by writing the polynomial and using synthetic division to find if the number 2 is a root of the polynomial [tex]\(F(x) = 3x^2 - 11x + 10\)[/tex].
The synthetic division process is shown below:
[tex]\[2 \ \left|\begin{array}{ccc} 3 & -11 & 10 \\ & 6 & -10 \\ \hline 3 & -5 & 0 \\ \end{array}\right.\][/tex]
Here's how it works step-by-step:
1. Write down the coefficients of the polynomial [tex]\(F(x)\)[/tex], which are [tex]\(3, -11, 10\)[/tex].
2. Place the 2 to the left (this is our test root).
3. Bring down the first coefficient (3) directly.
4. Multiply 2 by the value just written below the line (3), giving [tex]\(2 \times 3 = 6\)[/tex]. Write this under the second coefficient (-11).
5. Add the values in the second column [tex]\((-11 + 6 = -5)\)[/tex].
6. Multiply 2 by the value just written below the line (-5), giving [tex]\(2 \times -5 = -10\)[/tex]. Write this under the third coefficient (10).
7. Add the values in the third column [tex]\((10 + -10 = 0)\)[/tex].
After performing the synthetic division, we end up with:
[tex]\[2 \ \left|\begin{array}{ccc} 3 & -11 & 10 \\ & 6 & -10 \\ \hline 3 & -5 & 0 \\ \end{array}\right.\][/tex]
So, the division results in coefficients for a new polynomial (3x - 5) and a remainder of 0.
From this, we can deduce the following:
- Since the remainder is 0, 2 is indeed a root of [tex]\(F(x) = 3x^2 - 11x + 10\)[/tex].
- Because 2 is a root, [tex]\((x - 2)\)[/tex] is a factor of [tex]\(F(x)\)[/tex].
- The quotient polynomial obtained from the synthetic division is [tex]\(3x - 5\)[/tex].
Now let's evaluate each of the given statements:
A. The number -2 is a root of [tex]\(F(x) = 3x^2 - 11x + 10\)[/tex]. → False. The root is 2, not -2.
B. The number 2 is a root of [tex]\(F(x) = 3x^2 - 11x + 10\)[/tex]. → True.
C. [tex]\((x - 2)\)[/tex] is a factor of [tex]\(3x^2 - 11x + 10\)[/tex]. → True.
D. [tex]\(\left(3x^2 - 11x + 10\right) \div (x-2) = 3x - 5.\)[/tex] → True.
E. [tex]\((x + 2)\)[/tex] is a factor of [tex]\(3x^2 - 11x + 10\)[/tex]. → False. Only [tex]\((x - 2)\)[/tex] is a factor.
F. [tex]\(\left(3x^2 - 11x + 10\right) \div (x + 2) = 3x - 5\)[/tex]. → False, since [tex]\((x + 2)\)[/tex] is not a factor.
Thus, the correct statements are:
B. The number 2 is a root of [tex]\(F(x) = 3x^2 - 11x + 10\)[/tex].
C. [tex]\((x - 2)\)[/tex] is a factor of [tex]\(3x^2 - 11x + 10\)[/tex].
D. [tex]\(\left(3x^2 - 11x + 10\right) \div (x-2) = 3x - 5\)[/tex].
Therefore, the indices of the true statements are:
[tex]\[ [2, 3, 4] \][/tex]
We greatly appreciate every question and answer you provide. Keep engaging and finding the best solutions. This community is the perfect place to learn and grow together. Your questions deserve reliable answers. Thanks for visiting IDNLearn.com, and see you again soon for more helpful information.