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Sagot :
To determine the power conducted by the resistor, we can use the formula for electrical power based on voltage and current:
[tex]\[ P = V \times I \][/tex]
Where:
- [tex]\( P \)[/tex] is the power in watts (W)
- [tex]\( V \)[/tex] is the voltage in volts (V)
- [tex]\( I \)[/tex] is the current in amperes (A)
Given the problem:
- The voltage drop ([tex]\( V \)[/tex]) is 24.0 V
- The current ([tex]\( I \)[/tex]) is 0.800 A
Substitute the given values into the formula:
[tex]\[ P = 24.0 \, \text{V} \times 0.800 \, \text{A} \][/tex]
Now multiply the values:
[tex]\[ P = 24.0 \times 0.800 \][/tex]
[tex]\[ P = 19.2 \, \text{W} \][/tex]
So, the power conducted by the resistor is 19.2 watts. Therefore, the correct answer is:
A. 19.2 W
[tex]\[ P = V \times I \][/tex]
Where:
- [tex]\( P \)[/tex] is the power in watts (W)
- [tex]\( V \)[/tex] is the voltage in volts (V)
- [tex]\( I \)[/tex] is the current in amperes (A)
Given the problem:
- The voltage drop ([tex]\( V \)[/tex]) is 24.0 V
- The current ([tex]\( I \)[/tex]) is 0.800 A
Substitute the given values into the formula:
[tex]\[ P = 24.0 \, \text{V} \times 0.800 \, \text{A} \][/tex]
Now multiply the values:
[tex]\[ P = 24.0 \times 0.800 \][/tex]
[tex]\[ P = 19.2 \, \text{W} \][/tex]
So, the power conducted by the resistor is 19.2 watts. Therefore, the correct answer is:
A. 19.2 W
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