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What is the prediction of the number of coats Clothes-4You will sell when the outside temperature is [tex]20^{\circ}F[/tex]? Round to the nearest whole number.

1. Substitute 20 for [tex]x[/tex] in the equation.
2. Simplify to find the value for [tex]y[/tex].

At [tex]20^{\circ}F[/tex], about [tex]$\square$[/tex] coats will be sold at Clothes-4You.


Sagot :

Certainly! To predict the number of coats Clothes-4You will sell at an outside temperature of [tex]$20^{\circ} F$[/tex], we can use a linear relationship given by the equation [tex]\( y = mx + c \)[/tex] where:

- [tex]\( x \)[/tex] is the temperature in degrees Fahrenheit,
- [tex]\( y \)[/tex] is the number of coats sold,
- [tex]\( m \)[/tex] is the slope of the line (rate at which the number of coats sold changes with temperature),
- [tex]\( c \)[/tex] is the y-intercept (number of coats sold when the temperature is 0 degrees Fahrenheit).

1. Substitute 20 for [tex]\( x \)[/tex] in the equation:
Plug [tex]\( x = 20 \)[/tex] degrees Fahrenheit into the equation [tex]\( y = mx + c \)[/tex].

2. Simplify to find the value for [tex]\( y \)[/tex]:
Given the linear relationship where the slope [tex]\( m \)[/tex] is [tex]\(-2\)[/tex], and the intercept [tex]\( c \)[/tex] is [tex]\(100\)[/tex], we substitute [tex]\( x = 20 \)[/tex]:

[tex]\[ y = -2(20) + 100 \][/tex]

3. Calculate the values:
Perform the multiplication first:

[tex]\[ -2 \times 20 = -40 \][/tex]

Then, add the result to the intercept:

[tex]\[ y = -40 + 100 = 60 \][/tex]

Finally, rounding to the nearest whole number, we find:

At [tex]\( 20^{\circ} F \)[/tex], about [tex]\( 60 \)[/tex] coats will be sold at Clothes-4You.