IDNLearn.com: Your go-to resource for finding precise and accurate answers. Ask any question and get a detailed, reliable answer from our community of experts.
Sagot :
To determine the number of molecules in 0.5 mole of [tex]\(P_2O_3\)[/tex], let us follow a step-by-step approach.
First, recall that 1 mole of any substance contains [tex]\(6.02 \times 10^{23}\)[/tex] particles (Avogadro's number). Here, we are dealing with molecules of [tex]\(P_2O_3\)[/tex].
1. Given:
- Avogadro's number: [tex]\(6.02 \times 10^{23}\)[/tex] particles per mole.
- Moles of [tex]\(P_2O_3\)[/tex]: 0.5 moles.
2. Calculate the number of molecules in 0.5 mole of [tex]\(P_2O_3\)[/tex]:
- Number of molecules = (Number of moles) [tex]\(\times\)[/tex] (Avogadro's number).
- Number of molecules = [tex]\(0.5 \times 6.02 \times 10^{23}\)[/tex].
3. Now, perform the multiplication:
- Number of molecules = [tex]\(3.01 \times 10^{23}\)[/tex].
Thus, there are [tex]\(3.01 \times 10^{23}\)[/tex] molecules in 0.5 mole of [tex]\(P_2O_3\)[/tex].
So, the coefficient is [tex]\(3.01\)[/tex] (in the green box) and the exponent is [tex]\(23\)[/tex] (in the yellow box).
First, recall that 1 mole of any substance contains [tex]\(6.02 \times 10^{23}\)[/tex] particles (Avogadro's number). Here, we are dealing with molecules of [tex]\(P_2O_3\)[/tex].
1. Given:
- Avogadro's number: [tex]\(6.02 \times 10^{23}\)[/tex] particles per mole.
- Moles of [tex]\(P_2O_3\)[/tex]: 0.5 moles.
2. Calculate the number of molecules in 0.5 mole of [tex]\(P_2O_3\)[/tex]:
- Number of molecules = (Number of moles) [tex]\(\times\)[/tex] (Avogadro's number).
- Number of molecules = [tex]\(0.5 \times 6.02 \times 10^{23}\)[/tex].
3. Now, perform the multiplication:
- Number of molecules = [tex]\(3.01 \times 10^{23}\)[/tex].
Thus, there are [tex]\(3.01 \times 10^{23}\)[/tex] molecules in 0.5 mole of [tex]\(P_2O_3\)[/tex].
So, the coefficient is [tex]\(3.01\)[/tex] (in the green box) and the exponent is [tex]\(23\)[/tex] (in the yellow box).
Thank you for joining our conversation. Don't hesitate to return anytime to find answers to your questions. Let's continue sharing knowledge and experiences! For trustworthy answers, rely on IDNLearn.com. Thanks for visiting, and we look forward to assisting you again.