Explore IDNLearn.com to discover insightful answers from experts and enthusiasts alike. Join our platform to receive prompt and accurate responses from experienced professionals in various fields.
Sagot :
Let's tackle each part of the question step-by-step, providing a detailed solution to each.
### Part (a): Find the dot product [tex]\( v \cdot w \)[/tex]
Given vectors:
[tex]\[ v = \sqrt{3}i + 3j \][/tex]
[tex]\[ w = i + j \][/tex]
The dot product of two vectors [tex]\( v = [v_1, v_2] \)[/tex] and [tex]\( w = [w_1, w_2] \)[/tex] is given by:
[tex]\[ v \cdot w = v_1 \cdot w_1 + v_2 \cdot w_2 \][/tex]
In our case:
[tex]\[ v_1 = \sqrt{3}, \quad v_2 = 3 \][/tex]
[tex]\[ w_1 = 1, \quad w_2 = 1 \][/tex]
Now calculate the dot product:
[tex]\[ v \cdot w = (\sqrt{3} \cdot 1) + (3 \cdot 1) \][/tex]
[tex]\[ v \cdot w = \sqrt{3} + 3 \][/tex]
Hence:
[tex]\[ v \cdot w = \sqrt{3} + 3 \][/tex]
To give you the finalized value of dot product:
[tex]\[ v \cdot w = 4.732050807568877 \][/tex]
### Part (b): Find the angle [tex]\(\theta\)[/tex] between [tex]\(v\)[/tex] and [tex]\(w\)[/tex]
The angle [tex]\(\theta\)[/tex] between two vectors can be found using the formula:
[tex]\[ \cos \theta = \frac{v \cdot w}{\|v\| \|w\|} \][/tex]
First, calculate the magnitudes of [tex]\(v\)[/tex] and [tex]\(w\)[/tex]:
[tex]\[ \|v\| = \sqrt{(\sqrt{3})^2 + 3^2} = \sqrt{3 + 9} = \sqrt{12} = 2\sqrt{3} \][/tex]
[tex]\[ \|w\| = \sqrt{1^2 + 1^2} = \sqrt{1 + 1} = \sqrt{2} \][/tex]
Now substitute the values:
[tex]\[ \cos \theta = \frac{\sqrt{3} + 3}{2\sqrt{3} \cdot \sqrt{2}} = \frac{4.732050807568877}{2\sqrt{6}} \][/tex]
[tex]\[ \cos \theta = \frac{4.732050807568877}{4.898979485566356} \approx 0.965925826289068 \][/tex]
Therefore:
[tex]\[ \theta = \arccos(0.965925826289068) \approx 0.2617993877991502 \text{ radians} \][/tex]
To convert to degrees:
[tex]\[ \theta \approx 15.000000000000043^\circ \][/tex]
### Part (c): State whether the vectors are parallel, orthogonal, or neither
Two vectors are:
- Parallel if the cosine of the angle between them is ±1.
- Orthogonal if the dot product is 0.
Given the calculations:
- [tex]\(\cos(\theta) = 0.965925826289068\)[/tex], which is neither 1 nor -1.
- The dot product [tex]\(\sqrt{3} + 3\)[/tex] is not 0.
Hence:
The vectors [tex]\(v\)[/tex] and [tex]\(w\)[/tex] are neither parallel nor orthogonal.
### Final Answer:
(a) The dot product [tex]\( v \cdot w = 4.732050807568877 \)[/tex]
(b) The angle between [tex]\( v \)[/tex] and [tex]\( w \)[/tex] is approximately [tex]\( 0.2617993877991502 \)[/tex] radians or [tex]\( 15.000000000000043^\circ \)[/tex] degrees.
(c) The vectors are neither parallel nor orthogonal.
### Part (a): Find the dot product [tex]\( v \cdot w \)[/tex]
Given vectors:
[tex]\[ v = \sqrt{3}i + 3j \][/tex]
[tex]\[ w = i + j \][/tex]
The dot product of two vectors [tex]\( v = [v_1, v_2] \)[/tex] and [tex]\( w = [w_1, w_2] \)[/tex] is given by:
[tex]\[ v \cdot w = v_1 \cdot w_1 + v_2 \cdot w_2 \][/tex]
In our case:
[tex]\[ v_1 = \sqrt{3}, \quad v_2 = 3 \][/tex]
[tex]\[ w_1 = 1, \quad w_2 = 1 \][/tex]
Now calculate the dot product:
[tex]\[ v \cdot w = (\sqrt{3} \cdot 1) + (3 \cdot 1) \][/tex]
[tex]\[ v \cdot w = \sqrt{3} + 3 \][/tex]
Hence:
[tex]\[ v \cdot w = \sqrt{3} + 3 \][/tex]
To give you the finalized value of dot product:
[tex]\[ v \cdot w = 4.732050807568877 \][/tex]
### Part (b): Find the angle [tex]\(\theta\)[/tex] between [tex]\(v\)[/tex] and [tex]\(w\)[/tex]
The angle [tex]\(\theta\)[/tex] between two vectors can be found using the formula:
[tex]\[ \cos \theta = \frac{v \cdot w}{\|v\| \|w\|} \][/tex]
First, calculate the magnitudes of [tex]\(v\)[/tex] and [tex]\(w\)[/tex]:
[tex]\[ \|v\| = \sqrt{(\sqrt{3})^2 + 3^2} = \sqrt{3 + 9} = \sqrt{12} = 2\sqrt{3} \][/tex]
[tex]\[ \|w\| = \sqrt{1^2 + 1^2} = \sqrt{1 + 1} = \sqrt{2} \][/tex]
Now substitute the values:
[tex]\[ \cos \theta = \frac{\sqrt{3} + 3}{2\sqrt{3} \cdot \sqrt{2}} = \frac{4.732050807568877}{2\sqrt{6}} \][/tex]
[tex]\[ \cos \theta = \frac{4.732050807568877}{4.898979485566356} \approx 0.965925826289068 \][/tex]
Therefore:
[tex]\[ \theta = \arccos(0.965925826289068) \approx 0.2617993877991502 \text{ radians} \][/tex]
To convert to degrees:
[tex]\[ \theta \approx 15.000000000000043^\circ \][/tex]
### Part (c): State whether the vectors are parallel, orthogonal, or neither
Two vectors are:
- Parallel if the cosine of the angle between them is ±1.
- Orthogonal if the dot product is 0.
Given the calculations:
- [tex]\(\cos(\theta) = 0.965925826289068\)[/tex], which is neither 1 nor -1.
- The dot product [tex]\(\sqrt{3} + 3\)[/tex] is not 0.
Hence:
The vectors [tex]\(v\)[/tex] and [tex]\(w\)[/tex] are neither parallel nor orthogonal.
### Final Answer:
(a) The dot product [tex]\( v \cdot w = 4.732050807568877 \)[/tex]
(b) The angle between [tex]\( v \)[/tex] and [tex]\( w \)[/tex] is approximately [tex]\( 0.2617993877991502 \)[/tex] radians or [tex]\( 15.000000000000043^\circ \)[/tex] degrees.
(c) The vectors are neither parallel nor orthogonal.
We value your presence here. Keep sharing knowledge and helping others find the answers they need. This community is the perfect place to learn together. Thank you for choosing IDNLearn.com for your queries. We’re here to provide accurate answers, so visit us again soon.