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Solve for [tex]$x$[/tex]:
[tex]\[ 2 x^{-\frac{1}{2}} - 2 = 0 \][/tex]


Sagot :

Certainly! Let's solve the equation [tex]\(2 x^{-\frac{1}{2}} - 2 = 0\)[/tex] step by step.

1. Isolate the term involving [tex]\(x\)[/tex]:

The given equation is:
[tex]\[ 2 x^{-\frac{1}{2}} - 2 = 0 \][/tex]
Add 2 to both sides of the equation to isolate the term involving [tex]\(x\)[/tex]:
[tex]\[ 2 x^{-\frac{1}{2}} = 2 \][/tex]

2. Divide both sides by 2:

Next, divide both sides of the equation by 2 to further simplify:
[tex]\[ x^{-\frac{1}{2}} = 1 \][/tex]

3. Rewrite the exponent:

Recall that [tex]\(x^{-\frac{1}{2}}\)[/tex] is the same as [tex]\(1 / \sqrt{x}\)[/tex]. To eliminate the negative exponent, we rewrite the equation:
[tex]\[ x^{-\frac{1}{2}} = (\sqrt{x})^{-1} = 1 \][/tex]

4. Reciprocal properties:

Since [tex]\((x^{a})^{-1} = 1 / x^a\)[/tex], we know that [tex]\(\sqrt{x}\)[/tex] must be such that its reciprocal equals 1:
[tex]\[ \frac{1}{\sqrt{x}} = 1 \][/tex]

5. Solve for [tex]\(\sqrt{x}\)[/tex]:

Take the reciprocal of both sides to get:
[tex]\[ \sqrt{x} = 1 \][/tex]

6. Square both sides:

To solve for [tex]\(x\)[/tex], square both sides of the equation:
[tex]\[ (\sqrt{x})^2 = 1^2 \][/tex]
Simplifying, we have:
[tex]\[ x = 1 \][/tex]

The solution to the equation [tex]\(2 x^{-\frac{1}{2}} - 2 = 0\)[/tex] is:
[tex]\[ x = 1 \][/tex]
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