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If [tex]\frac{x}{2}+\frac{1}{3}=\frac{1}{4}[/tex], x must have the value of:

A) [tex]-\frac{1}{12}[/tex]
B) [tex]\frac{1}{6}[/tex]
C) [tex]-\frac{1}{6}[/tex]
D) [tex]\frac{1}{12}[/tex]
E) None of these


Sagot :

To solve the equation [tex]\(\frac{x}{2} + \frac{1}{3} = \frac{1}{4}\)[/tex] for [tex]\(x\)[/tex], we'll go through the following step-by-step process:

1. Isolate the term with [tex]\(x\)[/tex]:

Start by subtracting [tex]\(\frac{1}{3}\)[/tex] from both sides of the equation:
[tex]\[ \frac{x}{2} + \frac{1}{3} - \frac{1}{3} = \frac{1}{4} - \frac{1}{3} \][/tex]
This simplifies to:
[tex]\[ \frac{x}{2} = \frac{1}{4} - \frac{1}{3} \][/tex]

2. Find a common denominator to combine fractions:

The common denominator between 4 and 3 is 12. Convert the fractions accordingly:
[tex]\[ \frac{1}{4} = \frac{3}{12} \quad \text{and} \quad \frac{1}{3} = \frac{4}{12} \][/tex]
Now we can subtract the fractions:
[tex]\[ \frac{x}{2} = \frac{3}{12} - \frac{4}{12} = \frac{3 - 4}{12} = \frac{-1}{12} \][/tex]

3. Solve for [tex]\(x\)[/tex]:

To isolate [tex]\(x\)[/tex], multiply both sides of the equation by 2:
[tex]\[ x = 2 \times \frac{-1}{12} = \frac{-2}{12} = -\frac{1}{6} \][/tex]

Given this result, the value of [tex]\(x\)[/tex] must be [tex]\(-\frac{1}{6}\)[/tex].

Therefore, the answer is:
C) [tex]\(-\frac{1}{6}\)[/tex]