Explore a diverse range of topics and get answers from knowledgeable individuals on IDNLearn.com. Join our Q&A platform to get accurate and thorough answers to all your pressing questions.
Sagot :
Let's solve the problem step by step.
1. Count the total number of digits:
We have 20 random 4-digit numbers. Each number contributes 4 digits.
[tex]\[ \text{Total number of digits} = 20 \times 4 = 80 \][/tex]
2. Extract the digits from the 20 random numbers provided:
[tex]\[ \begin{aligned} 7918 &:\ 7, 9, 1, 8 \\ 7910 &:\ 7, 9, 1, 0 \\ 2546 &:\ 2, 5, 4, 6 \\ 1390 &:\ 1, 3, 9, 0 \\ 6075 &:\ 6, 0, 7, 5 \\ 1230 &:\ 1, 2, 3, 0 \\ 2386 &:\ 2, 3, 8, 6 \\ 0793 &:\ 0, 7, 9, 3 \\ 7359 &:\ 7, 3, 5, 9 \\ 3048 &:\ 3, 0, 4, 8 \\ 2816 &:\ 2, 8, 1, 6 \\ 6147 &:\ 6, 1, 4, 7 \\ 5978 &:\ 5, 9, 7, 8 \\ 5621 &:\ 5, 6, 2, 1 \\ 9732 &:\ 9, 7, 3, 2 \\ 9436 &:\ 9, 4, 3, 6 \\ 3806 &:\ 3, 8, 0, 6 \\ 5971 &:\ 5, 9, 7, 1 \\ 6173 &:\ 6, 1, 7, 3 \\ 1430 &:\ 1, 4, 3, 0 \\ \end{aligned} \][/tex]
3. Identify the digits representing students with brown eyes:
The digits 0, 1, 2, and 3 represent the [tex]$40\%$[/tex] of students with brown eyes.
4. Count the number of digits that are 0, 1, 2, or 3:
[tex]\[ \begin{aligned} \text{Digits} &:\ [7, 9, 1, 8, 7, 9, 1, 0, 2, 5, 4, 6, 1, 3, 9, 0, 6, 0, 7, 5, 1, 2, 3, 0, 2, 3, 8, 7, 0, 7, 9, 3, 7, 3, 5, 9, 3, 0, 4, 8, 2, 8, 1, 6, 6, 1, 4, 7, 5, 9, 7, 8, 5, 6, 2, 1, 9, 7, 3, 2, 9, 4, 3, 6, 3, 8, 0, 6, 5, 9, 7, 1, 6, 1, 7, 3, 1, 4, 3, 0] \\ & = [1, 0, 2, 1, 3, 0, 1, 2, 3, 0, 0, 3, 3, 2, 2, 0, 1, 1, 3, 2, 3, 0, 2, 1, 3] \\ \end{aligned} \][/tex]
Total count of brown eye digits = [tex]\( 3 (0's) + 7 (1's) + 6 (2's) + 9 (3's) = 25 \)[/tex]
5. Calculate the experimental probability:
Experimental Probability is calculated by dividing the number of favorable outcomes (digits representing brown eyes) by the total number of digits and then multiplying by 100 to express it as a percentage.
[tex]\[ \text{Experimental Probability} = \left( \frac{\text{Number of digits with 0, 1, 2, or 3}}{\text{Total Number of digits}} \right) \times 100 \][/tex]
[tex]\[ \text{Experimental Probability} = \left( \frac{25}{80} \right) \times 100 = 31.25 \% \][/tex]
Therefore, the experimental probability that in a group of 4 students, at least one of them has brown eyes is [tex]\(31.25\%\)[/tex].
1. Count the total number of digits:
We have 20 random 4-digit numbers. Each number contributes 4 digits.
[tex]\[ \text{Total number of digits} = 20 \times 4 = 80 \][/tex]
2. Extract the digits from the 20 random numbers provided:
[tex]\[ \begin{aligned} 7918 &:\ 7, 9, 1, 8 \\ 7910 &:\ 7, 9, 1, 0 \\ 2546 &:\ 2, 5, 4, 6 \\ 1390 &:\ 1, 3, 9, 0 \\ 6075 &:\ 6, 0, 7, 5 \\ 1230 &:\ 1, 2, 3, 0 \\ 2386 &:\ 2, 3, 8, 6 \\ 0793 &:\ 0, 7, 9, 3 \\ 7359 &:\ 7, 3, 5, 9 \\ 3048 &:\ 3, 0, 4, 8 \\ 2816 &:\ 2, 8, 1, 6 \\ 6147 &:\ 6, 1, 4, 7 \\ 5978 &:\ 5, 9, 7, 8 \\ 5621 &:\ 5, 6, 2, 1 \\ 9732 &:\ 9, 7, 3, 2 \\ 9436 &:\ 9, 4, 3, 6 \\ 3806 &:\ 3, 8, 0, 6 \\ 5971 &:\ 5, 9, 7, 1 \\ 6173 &:\ 6, 1, 7, 3 \\ 1430 &:\ 1, 4, 3, 0 \\ \end{aligned} \][/tex]
3. Identify the digits representing students with brown eyes:
The digits 0, 1, 2, and 3 represent the [tex]$40\%$[/tex] of students with brown eyes.
4. Count the number of digits that are 0, 1, 2, or 3:
[tex]\[ \begin{aligned} \text{Digits} &:\ [7, 9, 1, 8, 7, 9, 1, 0, 2, 5, 4, 6, 1, 3, 9, 0, 6, 0, 7, 5, 1, 2, 3, 0, 2, 3, 8, 7, 0, 7, 9, 3, 7, 3, 5, 9, 3, 0, 4, 8, 2, 8, 1, 6, 6, 1, 4, 7, 5, 9, 7, 8, 5, 6, 2, 1, 9, 7, 3, 2, 9, 4, 3, 6, 3, 8, 0, 6, 5, 9, 7, 1, 6, 1, 7, 3, 1, 4, 3, 0] \\ & = [1, 0, 2, 1, 3, 0, 1, 2, 3, 0, 0, 3, 3, 2, 2, 0, 1, 1, 3, 2, 3, 0, 2, 1, 3] \\ \end{aligned} \][/tex]
Total count of brown eye digits = [tex]\( 3 (0's) + 7 (1's) + 6 (2's) + 9 (3's) = 25 \)[/tex]
5. Calculate the experimental probability:
Experimental Probability is calculated by dividing the number of favorable outcomes (digits representing brown eyes) by the total number of digits and then multiplying by 100 to express it as a percentage.
[tex]\[ \text{Experimental Probability} = \left( \frac{\text{Number of digits with 0, 1, 2, or 3}}{\text{Total Number of digits}} \right) \times 100 \][/tex]
[tex]\[ \text{Experimental Probability} = \left( \frac{25}{80} \right) \times 100 = 31.25 \% \][/tex]
Therefore, the experimental probability that in a group of 4 students, at least one of them has brown eyes is [tex]\(31.25\%\)[/tex].
We appreciate every question and answer you provide. Keep engaging and finding the best solutions. This community is the perfect place to learn and grow together. IDNLearn.com provides the best answers to your questions. Thank you for visiting, and come back soon for more helpful information.