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7. For the data set with [tex]\mu = 275[/tex] and [tex]\sigma = 25[/tex], what percent of the data is between the following ranges?

- 250 and 300
- 300 and 350
- 200 and 350
- 225 and 300
- below 275
- 275 and 325


Sagot :

Let's solve the problem step-by-step and find the percentage of data within the specified ranges for a data set with a mean ([tex]$\mu$[/tex]) of 275 and a standard deviation ([tex]$\sigma$[/tex]) of 25:

1. Calculating the percentage of data between 250 and 300:

To find this percentage, we need to determine the area under the normal distribution curve between these two points.
[tex]\[ \text{Percent between 250 and 300} \approx 68.27\% \][/tex]

2. Calculating the percentage of data between 300 and 350:

Similarly, the area under the normal distribution curve between 300 and 350 needs to be calculated.
[tex]\[ \text{Percent between 300 and 350} \approx 15.73\% \][/tex]

3. Calculating the percentage of data between 200 and 350:

This involves finding the area under the normal distribution curve from 200 to 350.
[tex]\[ \text{Percent between 200 and 350} \approx 99.73\% \][/tex]

4. Calculating the percentage of data between 225 and 300:

The area under the normal distribution curve from 225 to 300 needs to be determined.
[tex]\[ \text{Percent between 225 and 300} \approx 81.86\% \][/tex]

5. Calculating the percentage of data below 275:

The percentage of the data below the mean of 275.
[tex]\[ \text{Percent below 275} = 50\% \][/tex]

6. Calculating the percentage of data between 275 and 325:

Lastly, the area under the normal distribution curve from 275 to 325.
[tex]\[ \text{Percent between 275 and 325} \approx 47.72\% \][/tex]

To summarize:

- The percent of data between 250 and 300 is approximately 68.27%.
- The percent of data between 300 and 350 is approximately 15.73%.
- The percent of data between 200 and 350 is approximately 99.73%.
- The percent of data between 225 and 300 is approximately 81.86%.
- The percent of data below 275 is 50%.
- The percent of data between 275 and 325 is approximately 47.72%.