To solve the problem of dividing [tex]\(-1.212 \text{ mL}\)[/tex] by [tex]\(15.118 \text{ mL}\)[/tex] and reporting the final answer rounded to two decimal places, follow these steps:
1. Division:
First, divide the given numerator by the denominator:
[tex]\[
-\frac{1.212 \text{ mL}}{15.118 \text{ mL}}
\][/tex]
Performing the division gives us approximately [tex]\(-0.08016933456806455\)[/tex].
2. Rounding:
Next, we round the result to two decimal places. To do this, we look at the third decimal place to determine how to round the second decimal place:
[tex]\[
-0.08016933456806455 \quad \text{(rounded to two decimal places)}
\][/tex]
Seeing that the third decimal place is 0 which is less than 5, we round down, resulting in [tex]\(-0.08\)[/tex].
3. Conclusion:
Therefore, the final answer to the division [tex]\(-\frac{1.212 \text{ mL}}{15.118 \text{ mL}}\)[/tex], rounded to two decimal places, is [tex]\(-0.08\)[/tex].
Additionally, to address the values given for 15.11 mL, 15.12 mL, and 15.120 mL, it's important to note:
- The question asks to compare these values and determine the final reporting value when rounded to two decimal places.
- Among the provided values (15.11, 15.12, 15.120), rounding to two decimal places keeps 15.12 mL (ignoring the third digit which matches in significance).
Ultimately, for the calculations involving [tex]\( \frac{-1.212 \text{ mL}}{15.118 \text{ mL}} \)[/tex]:
- The rounded result of [tex]\(-0.08\)[/tex] correctly applies a rounding approach to the given division.
- And the selected value from the choices is [tex]\( 15.12 \text{ mL} \)[/tex] aligning with the question expectation.
In summary:
[tex]\[
\boxed{-0.08} \quad \text{and} \quad 15.12 \text{ mL}
\][/tex] is your final reported answers.
