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Calculate the volume percent of solute in each of the solutions.

A solution made by adding 18.7 mL of methyl alcohol to enough water to give 515 mL of solution.
[tex]\[ \%(v / v) = \ \_\_\_\% \][/tex]

A solution made by adding 76.1 mL of ethylene glycol to enough water to give 227 mL of solution.
[tex]\[ \%(v / v) = \ \_\_\_\% \][/tex]


Sagot :

Let's calculate the volume percent ([tex]\( \%(v/v) \)[/tex]) of solute for each of the solutions separately.

### Solution 1: Methyl Alcohol
Given:
- Volume of methyl alcohol (solute): 18.7 mL
- Total volume of the solution: 515 mL

To calculate the volume percent of methyl alcohol in the solution, we use the following formula:

[tex]\[ \%(v/v) = \left( \frac{\text{Volume of solute}}{\text{Total volume of solution}} \right) \times 100 \][/tex]

Plugging in the given values:

[tex]\[ \%(v/v) = \left( \frac{18.7}{515} \right) \times 100 \][/tex]

The volume percent ([tex]\( \%(v/v) \)[/tex]) of methyl alcohol in the solution is:

[tex]\[ \%(v/v) \approx 3.63 \% \][/tex]

### Solution 2: Ethylene Glycol
Given:
- Volume of ethylene glycol (solute): 76.1 mL
- Total volume of the solution: 227 mL

To calculate the volume percent of ethylene glycol in the solution, we use the same formula as above:

[tex]\[ \%(v/v) = \left( \frac{\text{Volume of solute}}{\text{Total volume of solution}} \right) \times 100 \][/tex]

Plugging in the given values:

[tex]\[ \%(v/v) = \left( \frac{76.1}{227} \right) \times 100 \][/tex]

The volume percent ([tex]\( \%(v/v) \)[/tex]) of ethylene glycol in the solution is:

[tex]\[ \%(v/v) \approx 33.52 \% \][/tex]

### Summary
- The volume percent of methyl alcohol in the first solution is approximately [tex]\(3.63\% \)[/tex].
- The volume percent of ethylene glycol in the second solution is approximately [tex]\(33.52\% \)[/tex].