Join the IDNLearn.com community and start finding the answers you need today. Discover reliable and timely information on any topic from our network of knowledgeable professionals.
Sagot :
Let's calculate the volume percent ([tex]\( \%(v/v) \)[/tex]) of solute for each of the solutions separately.
### Solution 1: Methyl Alcohol
Given:
- Volume of methyl alcohol (solute): 18.7 mL
- Total volume of the solution: 515 mL
To calculate the volume percent of methyl alcohol in the solution, we use the following formula:
[tex]\[ \%(v/v) = \left( \frac{\text{Volume of solute}}{\text{Total volume of solution}} \right) \times 100 \][/tex]
Plugging in the given values:
[tex]\[ \%(v/v) = \left( \frac{18.7}{515} \right) \times 100 \][/tex]
The volume percent ([tex]\( \%(v/v) \)[/tex]) of methyl alcohol in the solution is:
[tex]\[ \%(v/v) \approx 3.63 \% \][/tex]
### Solution 2: Ethylene Glycol
Given:
- Volume of ethylene glycol (solute): 76.1 mL
- Total volume of the solution: 227 mL
To calculate the volume percent of ethylene glycol in the solution, we use the same formula as above:
[tex]\[ \%(v/v) = \left( \frac{\text{Volume of solute}}{\text{Total volume of solution}} \right) \times 100 \][/tex]
Plugging in the given values:
[tex]\[ \%(v/v) = \left( \frac{76.1}{227} \right) \times 100 \][/tex]
The volume percent ([tex]\( \%(v/v) \)[/tex]) of ethylene glycol in the solution is:
[tex]\[ \%(v/v) \approx 33.52 \% \][/tex]
### Summary
- The volume percent of methyl alcohol in the first solution is approximately [tex]\(3.63\% \)[/tex].
- The volume percent of ethylene glycol in the second solution is approximately [tex]\(33.52\% \)[/tex].
### Solution 1: Methyl Alcohol
Given:
- Volume of methyl alcohol (solute): 18.7 mL
- Total volume of the solution: 515 mL
To calculate the volume percent of methyl alcohol in the solution, we use the following formula:
[tex]\[ \%(v/v) = \left( \frac{\text{Volume of solute}}{\text{Total volume of solution}} \right) \times 100 \][/tex]
Plugging in the given values:
[tex]\[ \%(v/v) = \left( \frac{18.7}{515} \right) \times 100 \][/tex]
The volume percent ([tex]\( \%(v/v) \)[/tex]) of methyl alcohol in the solution is:
[tex]\[ \%(v/v) \approx 3.63 \% \][/tex]
### Solution 2: Ethylene Glycol
Given:
- Volume of ethylene glycol (solute): 76.1 mL
- Total volume of the solution: 227 mL
To calculate the volume percent of ethylene glycol in the solution, we use the same formula as above:
[tex]\[ \%(v/v) = \left( \frac{\text{Volume of solute}}{\text{Total volume of solution}} \right) \times 100 \][/tex]
Plugging in the given values:
[tex]\[ \%(v/v) = \left( \frac{76.1}{227} \right) \times 100 \][/tex]
The volume percent ([tex]\( \%(v/v) \)[/tex]) of ethylene glycol in the solution is:
[tex]\[ \%(v/v) \approx 33.52 \% \][/tex]
### Summary
- The volume percent of methyl alcohol in the first solution is approximately [tex]\(3.63\% \)[/tex].
- The volume percent of ethylene glycol in the second solution is approximately [tex]\(33.52\% \)[/tex].
Thank you for being part of this discussion. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. Thank you for trusting IDNLearn.com with your questions. Visit us again for clear, concise, and accurate answers.