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Calculate the molarity of 0.800 mol of [tex]\text{Na}_2\text{S}[/tex] in 1.30 L of solution.

Molarity:

Sagot :

GinnyAnsweridn
Sure, I’d be happy to explain how to calculate the molarity step-by-step.

### Step-by-Step Solution:

1. Understand what molarity means: Molarity (M) is a measure of the concentration of a solute in a solution. It is defined as the number of moles of solute divided by the volume of the solution in liters.

2. Identify the given values:
- Number of moles of solute (Na2S): 0.800 mol
- Volume of the solution: 1.30 L

3. Set up the formula for molarity: The formula for molarity is
[tex]\[ M = \frac{\text{moles of solute}}{\text{volume of solution in liters}} \][/tex]

4. Plug in the given values:
[tex]\[ M = \frac{0.800 \text{ mol}}{1.30 \text{ L}} \][/tex]

5. Perform the division:
[tex]\[ M = 0.6153846153846154 \][/tex]

6. Express the molarity in proper significant figures:
Since the given values (0.800 mol and 1.30 L) both have three significant figures, the molarity should also be expressed to three significant figures.

So, the final molarity is:
[tex]\[ M = 0.615 \, \text{M} \][/tex]

Therefore, the molarity of 0.800 mol of Na2S in 1.30 L of solution is 0.615 M.
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