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To determine the slope of the trend line that passes through the points [tex]\((-3, 3)\)[/tex] and [tex]\( (18, 26)\)[/tex], we can use the slope formula:
[tex]\[ \text{slope} = \frac{y_2 - y_1}{x_2 - x_1} \][/tex]
First, assign the coordinates to [tex]\(x_1, y_1\)[/tex] and [tex]\(x_2, y_2\)[/tex]:
[tex]\[ (x_1, y_1) = (-3, 3) \][/tex]
[tex]\[ (x_2, y_2) = (18, 26) \][/tex]
Next, calculate the numerator [tex]\(y_2 - y_1\)[/tex]:
[tex]\[ y_2 - y_1 = 26 - 3 = 23 \][/tex]
Then, calculate the denominator [tex]\(x_2 - x_1\)[/tex]:
[tex]\[ x_2 - x_1 = 18 - (-3) = 18 + 3 = 21 \][/tex]
Finally, compute the slope:
[tex]\[ \text{slope} = \frac{y_2 - y_1}{x_2 - x_1} = \frac{23}{21} \][/tex]
Thus, the slope of the trend line passing through the points [tex]\((-3, 3)\)[/tex] and [tex]\( (18, 26)\)[/tex] is:
[tex]\[ \frac{23}{21} \][/tex]
The correct answer is:
[tex]\[ \frac{23}{21} \][/tex]
[tex]\[ \text{slope} = \frac{y_2 - y_1}{x_2 - x_1} \][/tex]
First, assign the coordinates to [tex]\(x_1, y_1\)[/tex] and [tex]\(x_2, y_2\)[/tex]:
[tex]\[ (x_1, y_1) = (-3, 3) \][/tex]
[tex]\[ (x_2, y_2) = (18, 26) \][/tex]
Next, calculate the numerator [tex]\(y_2 - y_1\)[/tex]:
[tex]\[ y_2 - y_1 = 26 - 3 = 23 \][/tex]
Then, calculate the denominator [tex]\(x_2 - x_1\)[/tex]:
[tex]\[ x_2 - x_1 = 18 - (-3) = 18 + 3 = 21 \][/tex]
Finally, compute the slope:
[tex]\[ \text{slope} = \frac{y_2 - y_1}{x_2 - x_1} = \frac{23}{21} \][/tex]
Thus, the slope of the trend line passing through the points [tex]\((-3, 3)\)[/tex] and [tex]\( (18, 26)\)[/tex] is:
[tex]\[ \frac{23}{21} \][/tex]
The correct answer is:
[tex]\[ \frac{23}{21} \][/tex]
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