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Is there a difference in the amount of airborne bacteria between carpeted and uncarpeted rooms?

In an experiment, seven rooms were carpeted and seven were left uncarpeted. The rooms were similar in size and function. After a suitable period, the concentration of bacteria in the air was measured (in units of bacteria per cubic foot) in all of these rooms. The data and summaries are as follows:

\begin{tabular}{lll}
& [tex]$\bar{x}$[/tex] & [tex]$s$[/tex] \\
Carpeted rooms & 184 & 22.0 \\
Uncarpeted rooms & 175 & 16.9
\end{tabular}

The researcher wants to investigate whether the presence of carpet is associated with either an increase or a decrease in the mean bacterial concentration in air. The numerical value of the two-sample [tex]$t$[/tex] statistic for this test is:

A. 0.858
B. 1.312
C. 3.818
D. 0.414


Sagot :

To determine whether there is a significant difference in the amount of airborne bacteria between carpeted and uncarpeted rooms, let's follow these steps:

1. State the hypothesis:
- Null hypothesis ([tex]\(H_0\)[/tex]): There is no difference in the mean bacterial concentration between carpeted and uncarpeted rooms.
- [tex]\(H_0: \mu_{\text{carpeted}} = \mu_{\text{uncarpeted}}\)[/tex]
- Alternative hypothesis ([tex]\(H_1\)[/tex]): There is a difference in the mean bacterial concentration between carpeted and uncarpeted rooms.
- [tex]\(H_1: \mu_{\text{carpeted}} \neq \mu_{\text{uncarpeted}}\)[/tex]

2. Collect the given data:
- Mean concentration in carpeted rooms ([tex]\(\bar{x}_{\text{carpeted}}\)[/tex]): 184
- Standard deviation in carpeted rooms ([tex]\(s_{\text{carpeted}}\)[/tex]): 22.0
- Number of carpeted rooms ([tex]\(n_{\text{carpeted}}\)[/tex]): 7
- Mean concentration in uncarpeted rooms ([tex]\(\bar{x}_{\text{uncarpeted}}\)[/tex]): 175
- Standard deviation in uncarpeted rooms ([tex]\(s_{\text{uncarpeted}}\)[/tex]): 16.9
- Number of uncarpeted rooms ([tex]\(n_{\text{uncarpeted}}\)[/tex]): 7

3. Calculate the standard error for the differences in means:
The formula for the standard error (SE) of the difference between two means is:
[tex]\[ SE_{\text{diff}} = \sqrt{\left( \frac{s_{\text{carpeted}}^2}{n_{\text{carpeted}}} \right) + \left( \frac{s_{\text{uncarpeted}}^2}{n_{\text{uncarpeted}}} \right)} \][/tex]
- Substituting the given values:
[tex]\[ SE_{\text{diff}} = \sqrt{\left( \frac{22.0^2}{7} \right) + \left( \frac{16.9^2}{7} \right)} \][/tex]
- Result:
[tex]\[ SE_{\text{diff}} = 10.485432070939456 \][/tex]

4. Calculate the t-statistic for testing the difference in means:
The formula for the t-statistic is:
[tex]\[ t = \frac{\bar{x}_{\text{carpeted}} - \bar{x}_{\text{uncarpeted}}}{SE_{\text{diff}}} \][/tex]
- Substituting the given values:
[tex]\[ t = \frac{184 - 175}{10.485432070939456} \][/tex]
- Result:
[tex]\[ t = 0.8583337280819971 \][/tex]

5. Determine the numerical value of the t-statistic:
- The calculated t-statistic is approximately 0.858.

Given the multiple choices provided:
- 0.858
- 1.312
- 3.818
- 0.414

The correct numerical value of the two-sample t statistic for this test, based on our calculations, is:

[tex]\[ \boxed{0.858} \][/tex]