From tech troubles to travel tips, IDNLearn.com has answers to all your questions. Discover reliable answers to your questions with our extensive database of expert knowledge.
Sagot :
Sure! Let's factor the trinomial [tex]\( 2c^2 + 11c + 5 \)[/tex].
1. Identify the trinomial: We start with [tex]\( 2c^2 + 11c + 5 \)[/tex].
2. Find two numbers that multiply to the product of the coefficient of [tex]\( c^2 \)[/tex] ([tex]\(2\)[/tex]) and the constant term ([tex]\(5\)[/tex]). The product of these two numbers should be [tex]\( 2 \times 5 = 10 \)[/tex]. These two numbers should also add up to the middle coefficient ([tex]\(11\)[/tex]).
The two numbers that satisfy these conditions are [tex]\( 10 \)[/tex] and [tex]\( 1 \)[/tex] because:
[tex]\[ 10 \times 1 = 10 \quad \text{and} \quad 10 + 1 = 11 \][/tex]
3. Rewrite the middle term using these two numbers: Instead of writing [tex]\( 11c \)[/tex], we write it as [tex]\( 10c + 1c \)[/tex]:
[tex]\[ 2c^2 + 11c + 5 = 2c^2 + 10c + c + 5 \][/tex]
4. Factor by grouping: Group the terms in pairs and factor out the greatest common factor (GCF) from each pair:
[tex]\[ 2c^2 + 10c + c + 5 = 2c(c + 5) + 1(c + 5) \][/tex]
5. Factor out the common binomial factor: Notice that [tex]\( (c + 5) \)[/tex] is a common factor:
[tex]\[ 2c(c + 5) + 1(c + 5) = (2c + 1)(c + 5) \][/tex]
So the correct factorization of [tex]\( 2c^2 + 11c + 5 \)[/tex] is [tex]\((2c + 1)(c + 5)\)[/tex].
Therefore, the correct numbers to fill in the blanks in [tex]\( (2c + \_)(c + \_) \)[/tex] are:
- First blank: [tex]\(1\)[/tex]
- Second blank: [tex]\(5\)[/tex]
Hence, the factorization is [tex]\((2c + 1)(c + 5)\)[/tex].
1. Identify the trinomial: We start with [tex]\( 2c^2 + 11c + 5 \)[/tex].
2. Find two numbers that multiply to the product of the coefficient of [tex]\( c^2 \)[/tex] ([tex]\(2\)[/tex]) and the constant term ([tex]\(5\)[/tex]). The product of these two numbers should be [tex]\( 2 \times 5 = 10 \)[/tex]. These two numbers should also add up to the middle coefficient ([tex]\(11\)[/tex]).
The two numbers that satisfy these conditions are [tex]\( 10 \)[/tex] and [tex]\( 1 \)[/tex] because:
[tex]\[ 10 \times 1 = 10 \quad \text{and} \quad 10 + 1 = 11 \][/tex]
3. Rewrite the middle term using these two numbers: Instead of writing [tex]\( 11c \)[/tex], we write it as [tex]\( 10c + 1c \)[/tex]:
[tex]\[ 2c^2 + 11c + 5 = 2c^2 + 10c + c + 5 \][/tex]
4. Factor by grouping: Group the terms in pairs and factor out the greatest common factor (GCF) from each pair:
[tex]\[ 2c^2 + 10c + c + 5 = 2c(c + 5) + 1(c + 5) \][/tex]
5. Factor out the common binomial factor: Notice that [tex]\( (c + 5) \)[/tex] is a common factor:
[tex]\[ 2c(c + 5) + 1(c + 5) = (2c + 1)(c + 5) \][/tex]
So the correct factorization of [tex]\( 2c^2 + 11c + 5 \)[/tex] is [tex]\((2c + 1)(c + 5)\)[/tex].
Therefore, the correct numbers to fill in the blanks in [tex]\( (2c + \_)(c + \_) \)[/tex] are:
- First blank: [tex]\(1\)[/tex]
- Second blank: [tex]\(5\)[/tex]
Hence, the factorization is [tex]\((2c + 1)(c + 5)\)[/tex].
We appreciate your presence here. Keep sharing knowledge and helping others find the answers they need. This community is the perfect place to learn together. Your search for solutions ends at IDNLearn.com. Thank you for visiting, and we look forward to helping you again.