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Sagot :
Sure! Let's expand and simplify the expression [tex]\((5v - 6)^2\)[/tex].
### Step-by-Step Solution:
1. Start with the given expression:
[tex]\[ (5v - 6)^2 \][/tex]
2. Use the algebraic identity for the square of a binomial:
[tex]\[ (a - b)^2 = a^2 - 2ab + b^2 \][/tex]
Here, [tex]\(a = 5v\)[/tex] and [tex]\(b = 6\)[/tex].
3. Apply the identity:
[tex]\[ (5v - 6)^2 = (5v)^2 - 2 \cdot (5v) \cdot 6 + 6^2 \][/tex]
4. Calculate each term:
- First term:
[tex]\[ (5v)^2 = 25v^2 \][/tex]
- Second term:
[tex]\[ -2 \cdot (5v) \cdot 6 = -60v \][/tex]
- Third term:
[tex]\[ 6^2 = 36 \][/tex]
5. Combine all the terms:
[tex]\[ (5v - 6)^2 = 25v^2 - 60v + 36 \][/tex]
Thus, the expanded and simplified form of [tex]\((5v - 6)^2\)[/tex] is:
[tex]\[ 25v^2 - 60v + 36 \][/tex]
### Step-by-Step Solution:
1. Start with the given expression:
[tex]\[ (5v - 6)^2 \][/tex]
2. Use the algebraic identity for the square of a binomial:
[tex]\[ (a - b)^2 = a^2 - 2ab + b^2 \][/tex]
Here, [tex]\(a = 5v\)[/tex] and [tex]\(b = 6\)[/tex].
3. Apply the identity:
[tex]\[ (5v - 6)^2 = (5v)^2 - 2 \cdot (5v) \cdot 6 + 6^2 \][/tex]
4. Calculate each term:
- First term:
[tex]\[ (5v)^2 = 25v^2 \][/tex]
- Second term:
[tex]\[ -2 \cdot (5v) \cdot 6 = -60v \][/tex]
- Third term:
[tex]\[ 6^2 = 36 \][/tex]
5. Combine all the terms:
[tex]\[ (5v - 6)^2 = 25v^2 - 60v + 36 \][/tex]
Thus, the expanded and simplified form of [tex]\((5v - 6)^2\)[/tex] is:
[tex]\[ 25v^2 - 60v + 36 \][/tex]
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