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Question 18 of 25

What is the solution to the equation below? Round your answer to two decimal places.

[tex] 5^x = 26 [/tex]

A. [tex] x = 2.19 [/tex]
B. [tex] x = 2.02 [/tex]
C. [tex] x = 0.50 [/tex]
D. [tex] x = 1.41 [/tex]


Sagot :

To solve the equation [tex]\(5^x = 26\)[/tex], we'll need to use logarithms. Here is a step-by-step approach:

1. Take the Logarithm of Both Sides: Applying the logarithm on both sides of the equation helps us handle the exponent.
[tex]\[ \log(5^x) = \log(26) \][/tex]

2. Apply Logarithm Properties: Utilize the property of logarithms that allows us to bring the exponent in front of the log function:
[tex]\[ x \cdot \log(5) = \log(26) \][/tex]

3. Solve for [tex]\(x\)[/tex]: To isolate [tex]\(x\)[/tex], we divide both sides by [tex]\(\log(5)\)[/tex]:
[tex]\[ x = \frac{\log(26)}{\log(5)} \][/tex]

4. Calculate the Logarithms:
- Calculate [tex]\(\log(26)\)[/tex]
- Calculate [tex]\(\log(5)\)[/tex]

5. Divide the Results:
[tex]\[ x = \frac{\log(26)}{\log(5)} \][/tex]

6. Round to Two Decimal Places:
[tex]\[ x \approx 2.02 \][/tex]

Therefore, the solution to the equation [tex]\(5^x = 26\)[/tex], rounded to two decimal places, is:

[tex]\[ \boxed{x = 2.02} \][/tex]

Hence, the correct answer is:
B. [tex]\(x = 2.02\)[/tex]