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Solve for [tex]\( x \)[/tex]:
[tex]\[ 3x = 6x - 2 \][/tex]


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CRA Alg1 Module 4 Day1 Factoring by grouping
3. Factor [tex]$x^2 + 10x + 15x + 150$[/tex] by grouping
[tex]$=$[/tex] Enter your next step here
[tex]$x+(0)+\frac{18}{48}+\frac{9}{16}$[/tex]
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Response:
CRA Algebra 1, Module 4, Day 1: Factoring by Grouping

3. Factor [tex]\( x^2 + 10x + 15x + 150 \)[/tex] by grouping.

Enter your next step here:

[tex]\[ x^2 + 10x + 15x + 150 = \][/tex]

[tex]\[ \][/tex]

Sagot :

GinnyAnsweridn
Let's factor the given polynomial [tex]\( x^2 + 10x + 15x + 150 \)[/tex] by grouping. We'll proceed step-by-step.

### Step 1: Group the terms
Group the polynomial into two pairs:
[tex]\[ x^2 + 10x + 15x + 150 \][/tex]
which can be written as:
[tex]\[ (x^2 + 10x) + (15x + 150) \][/tex]

### Step 2: Factor out the common factors in each group
Factor out the greatest common factor (GCF) from each group:
[tex]\[ x(x + 10) + 15(x + 10) \][/tex]

### Step 3: Factor out the common binomial factor
Now, notice that [tex]\( x + 10 \)[/tex] is a common factor in both groups:
[tex]\[ (x + 10)(x + 15) \][/tex]

### Conclusion
Thus, the factored form of the polynomial [tex]\( x^2 + 10x + 15x + 150 \)[/tex] is:
[tex]\[ (x + 10)(x + 15) \][/tex]
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