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Sagot :
To determine the power (P) of an electric circuit given the current (I) and the voltage (V), we can use the formula:
[tex]\[ P = I \times V \][/tex]
Where:
- [tex]\( I \)[/tex] is the current in amperes (A)
- [tex]\( V \)[/tex] is the voltage in volts (V)
- [tex]\( P \)[/tex] is the power in watts (W)
Given:
- [tex]\( I = 2.5 \)[/tex] amperes
- [tex]\( V = 120 \)[/tex] volts
Substituting the given values into the formula, we get:
[tex]\[ P = 2.5 \, \text{A} \times 120 \, \text{V} \][/tex]
Multiplying these together:
[tex]\[ P = 300 \, \text{W} \][/tex]
Therefore, the power of the electric circuit is:
[tex]\[ P = 300 \, \text{W} \][/tex]
The correct answer is [tex]\( \boxed{300 \text{ W}} \)[/tex].
[tex]\[ P = I \times V \][/tex]
Where:
- [tex]\( I \)[/tex] is the current in amperes (A)
- [tex]\( V \)[/tex] is the voltage in volts (V)
- [tex]\( P \)[/tex] is the power in watts (W)
Given:
- [tex]\( I = 2.5 \)[/tex] amperes
- [tex]\( V = 120 \)[/tex] volts
Substituting the given values into the formula, we get:
[tex]\[ P = 2.5 \, \text{A} \times 120 \, \text{V} \][/tex]
Multiplying these together:
[tex]\[ P = 300 \, \text{W} \][/tex]
Therefore, the power of the electric circuit is:
[tex]\[ P = 300 \, \text{W} \][/tex]
The correct answer is [tex]\( \boxed{300 \text{ W}} \)[/tex].
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