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What is the power [tex]\((P)\)[/tex] of an electric circuit with a current [tex]\((I)\)[/tex] of 2.5 A and a voltage [tex]\((V)\)[/tex] of 120 V? The formula for power is [tex]\(P = IV\)[/tex].

A. [tex]\(48 \Omega\)[/tex]
B. 48 W
C. 300 W
D. [tex]\(300 \Omega\)[/tex]


Sagot :

To determine the power (P) of an electric circuit given the current (I) and the voltage (V), we can use the formula:

[tex]\[ P = I \times V \][/tex]

Where:
- [tex]\( I \)[/tex] is the current in amperes (A)
- [tex]\( V \)[/tex] is the voltage in volts (V)
- [tex]\( P \)[/tex] is the power in watts (W)

Given:
- [tex]\( I = 2.5 \)[/tex] amperes
- [tex]\( V = 120 \)[/tex] volts

Substituting the given values into the formula, we get:

[tex]\[ P = 2.5 \, \text{A} \times 120 \, \text{V} \][/tex]

Multiplying these together:

[tex]\[ P = 300 \, \text{W} \][/tex]

Therefore, the power of the electric circuit is:

[tex]\[ P = 300 \, \text{W} \][/tex]

The correct answer is [tex]\( \boxed{300 \text{ W}} \)[/tex].
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