To determine how many moles are in [tex]\(7.22 \times 10^{23}\)[/tex] molecules of LiOH, we can use the concept that one mole of any substance contains Avogadro's number of particles, which is [tex]\(6.02 \times 10^{23}\)[/tex] particles per mole.
Here is the step-by-step solution:
1. Identify the given information:
- Number of molecules of LiOH: [tex]\(7.22 \times 10^{23}\)[/tex]
- Avogadro's number: [tex]\(6.02 \times 10^{23}\)[/tex] particles per mole
2. Set up the relationship to find the number of moles:
We use the formula:
[tex]\[
\text{number of moles} = \frac{\text{number of particles}}{\text{Avogadro's number}}
\][/tex]
3. Plug in the given values:
[tex]\[
\text{number of moles of LiOH} = \frac{7.22 \times 10^{23} \text{ molecules}}{6.02 \times 10^{23} \text{ molecules/mole}}
\][/tex]
4. Divide the numbers:
When we divide [tex]\(7.22 \times 10^{23}\)[/tex] by [tex]\(6.02 \times 10^{23}\)[/tex], the powers of [tex]\(10^{23}\)[/tex] cancel out, leaving us with:
[tex]\[
\text{number of moles of LiOH} = \frac{7.22}{6.02}
\][/tex]
5. Perform the division:
[tex]\[
\frac{7.22}{6.02} \approx 1.199
\][/tex]
Thus, there are approximately [tex]\(1.199\)[/tex] moles of LiOH in [tex]\(7.22 \times 10^{23}\)[/tex] molecules of LiOH.
