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Jenny is tracking the monthly sales totals for her boutique. The given piecewise function represents the boutique's monthly sales, in dollars, where [tex]$x$[/tex] represents the number of months since Jenny began tracking the data.

[tex]
f(x)=\left\{\begin{array}{ll}
4,000(1.1)^x, & 0 \leq x\ \textless \ 3 \\
100 x+5,024, & 3 \leq x\ \textless \ 6 \\
-x^2+5 x+5,630, & 6\ \textless \ x \leq 8
\end{array}\right.
[/tex]

What were the boutique's monthly sales when Jenny first began tracking the data?

A. [tex]$\$[/tex] 5,324[tex]$

B. $[/tex]\[tex]$ 4,000$[/tex]

C. [tex]$\$[/tex] 4,400[tex]$

D. $[/tex]\[tex]$ 5,616$[/tex]


Sagot :

To determine the boutique's monthly sales when Jenny first began tracking the data, we need to evaluate the given piecewise function at [tex]\( x = 0 \)[/tex].

The piecewise function is:
[tex]\[ f(x)=\left\{\begin{array}{ll} 4,000(1.1)^x, & 0 \leq x<3 \\ 100 x+5,024, & 3 \leq x<6 \\ -x^2+5 x+5,630, & 6
Since [tex]\( x = 0 \)[/tex] falls within the range [tex]\( 0 \leq x < 3 \)[/tex], we use the first part of the piecewise function:
[tex]\[ f(x) = 4,000(1.1)^x \][/tex]

Substitute [tex]\( x = 0 \)[/tex] into this expression:
[tex]\[ f(0) = 4,000 (1.1)^0 \][/tex]

Since any number raised to the power of 0 is 1:
[tex]\[ (1.1)^0 = 1 \][/tex]

Therefore:
[tex]\[ f(0) = 4,000 \times 1 = 4,000 \][/tex]

So, the boutique's monthly sales when Jenny first began tracking the data were [tex]$4,000. Thus, the correct answer is: B. $[/tex]4,000