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4. The number of villages with respect to their population as per the India Census 2011 is given below.

[tex]\[
\begin{tabular}{|l|l|l|l|l|l|l|}
\hline
Population (in thousands) & 12 & 5 & 30 & 20 & 15 & 8 \\
\hline
Villages & 20 & 15 & 32 & 35 & 36 & 7 \\
\hline
\end{tabular}
\][/tex]

Find the average population in each village.


Sagot :

Certainly! Let's go through the process step-by-step to find the average population per village based on the given data.

### Step-by-Step Solution

1. List the given data:
- Population (in thousands): [tex]\( [12, 5, 30, 20, 15, 8] \)[/tex]
- Number of villages: [tex]\( [20, 15, 32, 35, 36, 7] \)[/tex]

2. Calculate the sum of the populations:
[tex]\[ 12 + 5 + 30 + 20 + 15 + 8 = 90 \text{ thousand} \][/tex]
So, the total population in thousands is 90 thousand.

3. Calculate the sum of the villages:
[tex]\[ 20 + 15 + 32 + 35 + 36 + 7 = 145 \][/tex]
So, the total number of villages is 145.

4. Find the average population per village:
To find the average population per village, we divide the total population by the total number of villages:
[tex]\[ \text{Average population per village (in thousands)} = \frac{\text{Total population (in thousands)}}{\text{Total number of villages}} \][/tex]
Substituting the values:
[tex]\[ \text{Average population per village (in thousands)} = \frac{90}{145} \approx 0.6207 \text{ thousand} \][/tex]

5. Convert the average population per village to actual population count:
The population was initially given in thousands. To convert it to the actual number of people, we multiply by 1000:
[tex]\[ \text{Average population per village} = 0.6207 \times 1000 = 620.7 \][/tex]

### Conclusion

- The total population in thousands is 90.
- The total number of villages is 145.
- The average population per village in thousands is about 0.621.
- The actual average population per village is approximately 620.7 people.

Thus, the detailed step-by-step answer to finding the average population in each village is that, on average, each village has about 620.7 people.