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A pea plant with genotype [tex]PP[/tex] (purple flowers) mates with a plant with genotype [tex]pp[/tex] (white flowers). The dominant allele [tex]P[/tex] codes for purple flowers. The probability that the offspring will have purple flowers is [tex]\square[/tex]. If an offspring from this cross mates with a [tex]pp[/tex] plant, the probability of the homozygous dominant genotype for the flowers will be [tex]\square[/tex].

\begin{tabular}{|c|c|c|}
\hline & P & P \\
\hline p & Pp & Pp \\
\hline p & Pp & Pp \\
\hline
\end{tabular}

\begin{tabular}{|c|c|c|}
\hline & P & p \\
\hline p & Pp & pp \\
\hline p & Pp & pp \\
\hline
\end{tabular}


Sagot :

Let's go through the problem step by step:

1. Cross between PP (purple) and pp (white):

- Given that P is the dominant allele for purple flowers and p is the recessive allele for white flowers.
- A pea plant with genotype PP will always pass on the P allele.
- A pea plant with genotype pp will always pass on the p allele.

Performing the cross (PP x pp):

[tex]\[ \begin{array}{|c|c|c|} \hline & P & P \\ \hline p & Pp & Pp \\ \hline p & Pp & Pp \\ \hline \end{array} \][/tex]

All offspring will have the genotype Pp (heterozygous purple), meaning all offspring will have purple flowers. Therefore, the possibility that the offspring will have purple flowers is 100%.

2. Cross between offspring (Pp) from the first cross and pp (white):

Performing the cross (Pp x pp):

[tex]\[ \begin{array}{|c|c|c|} \hline & P & p \\ \hline p & Pp & pp \\ \hline p & Pp & pp \\ \hline \end{array} \][/tex]

The results show:
- 50% chance for Pp (heterozygous purple)
- 50% chance for pp (homozygous white)

Therefore, there is a 0% chance of an offspring being homozygous dominant (PP) because the parent with the pp genotype cannot contribute a P allele.

Summarizing the answers:

1. The possibility that the offspring will have purple flowers is 100%.
2. The possibility of a homozygous dominant genotype for the flowers is 0%.

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