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Sagot :
Let's go through the problem step by step:
1. Cross between PP (purple) and pp (white):
- Given that P is the dominant allele for purple flowers and p is the recessive allele for white flowers.
- A pea plant with genotype PP will always pass on the P allele.
- A pea plant with genotype pp will always pass on the p allele.
Performing the cross (PP x pp):
[tex]\[ \begin{array}{|c|c|c|} \hline & P & P \\ \hline p & Pp & Pp \\ \hline p & Pp & Pp \\ \hline \end{array} \][/tex]
All offspring will have the genotype Pp (heterozygous purple), meaning all offspring will have purple flowers. Therefore, the possibility that the offspring will have purple flowers is 100%.
2. Cross between offspring (Pp) from the first cross and pp (white):
Performing the cross (Pp x pp):
[tex]\[ \begin{array}{|c|c|c|} \hline & P & p \\ \hline p & Pp & pp \\ \hline p & Pp & pp \\ \hline \end{array} \][/tex]
The results show:
- 50% chance for Pp (heterozygous purple)
- 50% chance for pp (homozygous white)
Therefore, there is a 0% chance of an offspring being homozygous dominant (PP) because the parent with the pp genotype cannot contribute a P allele.
Summarizing the answers:
1. The possibility that the offspring will have purple flowers is 100%.
2. The possibility of a homozygous dominant genotype for the flowers is 0%.
These can be selected from the drop-down menus accordingly.
1. Cross between PP (purple) and pp (white):
- Given that P is the dominant allele for purple flowers and p is the recessive allele for white flowers.
- A pea plant with genotype PP will always pass on the P allele.
- A pea plant with genotype pp will always pass on the p allele.
Performing the cross (PP x pp):
[tex]\[ \begin{array}{|c|c|c|} \hline & P & P \\ \hline p & Pp & Pp \\ \hline p & Pp & Pp \\ \hline \end{array} \][/tex]
All offspring will have the genotype Pp (heterozygous purple), meaning all offspring will have purple flowers. Therefore, the possibility that the offspring will have purple flowers is 100%.
2. Cross between offspring (Pp) from the first cross and pp (white):
Performing the cross (Pp x pp):
[tex]\[ \begin{array}{|c|c|c|} \hline & P & p \\ \hline p & Pp & pp \\ \hline p & Pp & pp \\ \hline \end{array} \][/tex]
The results show:
- 50% chance for Pp (heterozygous purple)
- 50% chance for pp (homozygous white)
Therefore, there is a 0% chance of an offspring being homozygous dominant (PP) because the parent with the pp genotype cannot contribute a P allele.
Summarizing the answers:
1. The possibility that the offspring will have purple flowers is 100%.
2. The possibility of a homozygous dominant genotype for the flowers is 0%.
These can be selected from the drop-down menus accordingly.
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