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What is the common ratio in this sequence: [tex]$5, 15, 45, 135$[/tex]?

A. [tex]\frac{1}{3}[/tex]
B. -3
C. 3
D. 5


Sagot :

To determine the common ratio in the given sequence [tex]\(5, 15, 45, 135\)[/tex], let's follow these steps:

1. Identify the terms of the sequence:

The first term is [tex]\(5\)[/tex], the second term is [tex]\(15\)[/tex], the third term is [tex]\(45\)[/tex], and the fourth term is [tex]\(135\)[/tex].

2. Calculate the ratio between consecutive terms:

The common ratio [tex]\(r\)[/tex] can be found by dividing any term by the previous term.

Let's calculate the ratio using the first and second term:
[tex]\[ r = \frac{15}{5} = 3 \][/tex]

Next, we will verify this ratio using the second and third term:
[tex]\[ \frac{45}{15} = 3 \][/tex]

Finally, we confirm the consistency of the ratio using the third and fourth term:
[tex]\[ \frac{135}{45} = 3 \][/tex]

3. Conclusion:

Since the ratio between each pair of consecutive terms is consistently [tex]\(3\)[/tex], the common ratio for the sequence is [tex]\(3\)[/tex].

Therefore, the correct answer is:
[tex]\[ \boxed{3} \][/tex]