IDNLearn.com: Your one-stop platform for getting reliable answers to any question. Discover in-depth answers from knowledgeable professionals, providing you with the information you need.
Sagot :
To find the volume of a cone with a given radius and height, we use the formula for the volume of a cone:
[tex]\[ V = \frac{1}{3} \pi r^2 h \][/tex]
where:
- [tex]\( V \)[/tex] is the volume of the cone
- [tex]\( r \)[/tex] is the radius of the base of the cone
- [tex]\( h \)[/tex] is the height of the cone
- [tex]\( \pi \)[/tex] (pi) is a mathematical constant approximately equal to 3.14159.
Given:
- Radius ([tex]\( r \)[/tex]) = 4 feet
- Height ([tex]\( h \)[/tex]) = 9 feet
1. First, we square the radius:
[tex]\[ r^2 = 4^2 = 16 \][/tex]
2. Next, we multiply this squared radius by the height:
[tex]\[ 16 \times 9 = 144 \][/tex]
3. We then multiply the product by [tex]\(\pi\)[/tex]:
[tex]\[ 144 \times \pi \approx 144 \times 3.14159 \approx 452.38934 \][/tex]
4. Finally, we take one-third of this product to find the volume:
[tex]\[ V \approx \frac{452.38934}{3} \approx 150.79645 \][/tex]
5. To match the required precision, we round this volume to two decimal places:
[tex]\[ V \approx 150.80 \][/tex]
So, the volume of the cone, rounded to two decimal places, is approximately [tex]\( 150.80 \)[/tex] cubic feet.
[tex]\[ V = \frac{1}{3} \pi r^2 h \][/tex]
where:
- [tex]\( V \)[/tex] is the volume of the cone
- [tex]\( r \)[/tex] is the radius of the base of the cone
- [tex]\( h \)[/tex] is the height of the cone
- [tex]\( \pi \)[/tex] (pi) is a mathematical constant approximately equal to 3.14159.
Given:
- Radius ([tex]\( r \)[/tex]) = 4 feet
- Height ([tex]\( h \)[/tex]) = 9 feet
1. First, we square the radius:
[tex]\[ r^2 = 4^2 = 16 \][/tex]
2. Next, we multiply this squared radius by the height:
[tex]\[ 16 \times 9 = 144 \][/tex]
3. We then multiply the product by [tex]\(\pi\)[/tex]:
[tex]\[ 144 \times \pi \approx 144 \times 3.14159 \approx 452.38934 \][/tex]
4. Finally, we take one-third of this product to find the volume:
[tex]\[ V \approx \frac{452.38934}{3} \approx 150.79645 \][/tex]
5. To match the required precision, we round this volume to two decimal places:
[tex]\[ V \approx 150.80 \][/tex]
So, the volume of the cone, rounded to two decimal places, is approximately [tex]\( 150.80 \)[/tex] cubic feet.
Thank you for contributing to our discussion. Don't forget to check back for new answers. Keep asking, answering, and sharing useful information. IDNLearn.com is dedicated to providing accurate answers. Thank you for visiting, and see you next time for more solutions.