To calculate the density of a block of iron given its mass and volume, follow these steps:
1. Identify the given values:
- Mass ([tex]\( m \)[/tex]) = 3152 kg
- Volume ([tex]\( V \)[/tex]) = 0.4 m[tex]\(^3\)[/tex]
2. Write down the density formula:
[tex]\[
\text{Density} (\rho) = \frac{\text{Mass} (m)}{\text{Volume} (V)}
\][/tex]
3. Substitute the given values into the formula:
[tex]\[
\rho = \frac{3152 \, \text{kg}}{0.4 \, \text{m}^3}
\][/tex]
4. Calculate the density:
[tex]\[
\rho = 7880 \, \text{kg} / \text{m}^3
\][/tex]
5. Round the answer to 1 decimal place (if necessary):
Since the value obtained for density is [tex]\( 7880.0 \, \text{kg} / \text{m}^3 \)[/tex], it already is a whole number. When rounded to 1 decimal place, it remains:
[tex]\[
\rho \approx 7880.0 \, \text{kg} / \text{m}^3
\][/tex]
So, the density of the block of iron is [tex]\( 7880.0 \, \text{kg} / \text{m}^3 \)[/tex].
