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The magnitude, [tex]M[/tex], of an earthquake is represented by the equation [tex]M=\frac{2}{3} \log \frac{E}{E_0}[/tex], where [tex]E[/tex] is the amount of energy released by the earthquake in joules, and [tex]E_0=10^{4.4}[/tex] is the assigned minimal measure released by an earthquake.

Which equation could be used to find the amount of energy released by an earthquake with a magnitude of 2.7?

Select the correct answer below:
A. [tex]4.05=\frac{E}{10^{44}}[/tex]
B. [tex]10^{4.05}=\frac{E}{10^{1.4}}[/tex]
C. [tex]10^{4.05} E=10^{4.4}[/tex]
D. [tex]10^{4.05}=\frac{10^{4.4}}{E}[/tex]


Sagot :

To determine the correct equation for finding the amount of energy released by an earthquake with a magnitude of 2.7, let's solve the equation step-by-step.

The given equation is:
[tex]\[ M = \frac{2}{3} \log \frac{E}{E_0} \][/tex]

We are given:
[tex]\[ E_0 = 10^{4.4} \][/tex]
[tex]\[ M = 2.7 \][/tex]

We need to find [tex]\( E \)[/tex]. Follow these steps:

1. Substitute [tex]\( M \)[/tex] and [tex]\( E_0 \)[/tex] into the equation:
[tex]\[ 2.7 = \frac{2}{3} \log \frac{E}{10^{4.4}} \][/tex]

2. Multiply both sides by [tex]\(\frac{3}{2}\)[/tex] to isolate the logarithm:
[tex]\[ 2.7 \times \frac{3}{2} = \log \frac{E}{10^{4.4}} \][/tex]
[tex]\[ 4.05 = \log \frac{E}{10^{4.4}} \][/tex]

3. Recall that the logarithm operation [tex]\(\log\)[/tex] here is with base 10. To remove the logarithm, raise both sides as powers of 10:
[tex]\[ 10^{4.05} = \frac{E}{10^{4.4}} \][/tex]

Hence, the correct equation to use in order to find the amount of energy released ([tex]\(E\)[/tex]) is:
[tex]\[ 10^{4.05} = \frac{E}{10^{4.4}} \][/tex]

Therefore, the correct answer is:
[tex]\[ 10^{4.05} = \frac{E}{10^{4.4}} \][/tex]
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