At IDNLearn.com, find answers to your most pressing questions from experts and enthusiasts alike. Find reliable solutions to your questions quickly and easily with help from our experienced experts.
Sagot :
Let's walk through how we find the residuals and calculate their sum.
### Step Two: Find the Residuals
Residuals are the differences between the observed [tex]\( y \)[/tex]-values and the predicted [tex]\( \dot{y} \)[/tex]-values using the regression line [tex]\( y = 2.9 + 0.34x \)[/tex].
Given the data:
[tex]\[ \{(5,5),(7,3),(9,9),(11,7),(13,5),(15,9)\} \][/tex]
And the predicted [tex]\( \dot{y} \)[/tex] values calculated using the regression line:
[tex]\[ \begin{aligned} \dot{y} \text{ for } x=5 & = 4.6 \\ \dot{y} \text{ for } x=7 & = 5.3 \\ \dot{y} \text{ for } x=9 & = 6.0 \\ \dot{y} \text{ for } x=11 & = 6.6 \\ \dot{y} \text{ for } x=13 & = 7.3 \\ \dot{y} \text{ for } x=15 & = 8.0 \\ \end{aligned} \][/tex]
We can find the residuals by subtracting the predicted [tex]\( \dot{y} \)[/tex] from the observed [tex]\( y \)[/tex]:
[tex]\[ \begin{aligned} \text{Residual for } x=5 & : 5 - 4.6 = 0.4 \\ \text{Residual for } x=7 & : 3 - 5.3 = -2.3 \\ \text{Residual for } x=9 & : 9 - 6.0 = 3.0 \\ \text{Residual for } x=11 & : 7 - 6.6 = 0.4 \\ \text{Residual for } x=13 & : 5 - 7.3 = -2.3 \\ \text{Residual for } x=15 & : 9 - 8.0 = 1.0 \\ \end{aligned} \][/tex]
Now, listing these residuals:
[tex]\[ [0.4, -2.3, 3.0, 0.4, -2.3, 1.0] \][/tex]
### Sum of the Residuals
The sum of the residuals is calculated by summing up all the individual residuals:
[tex]\[ 0.4 + (-2.3) + 3.0 + 0.4 + (-2.3) + 1.0 = 0.2 \][/tex]
Thus, the sum of the residuals is [tex]\( 0.2 \)[/tex].
### Step Two: Find the Residuals
Residuals are the differences between the observed [tex]\( y \)[/tex]-values and the predicted [tex]\( \dot{y} \)[/tex]-values using the regression line [tex]\( y = 2.9 + 0.34x \)[/tex].
Given the data:
[tex]\[ \{(5,5),(7,3),(9,9),(11,7),(13,5),(15,9)\} \][/tex]
And the predicted [tex]\( \dot{y} \)[/tex] values calculated using the regression line:
[tex]\[ \begin{aligned} \dot{y} \text{ for } x=5 & = 4.6 \\ \dot{y} \text{ for } x=7 & = 5.3 \\ \dot{y} \text{ for } x=9 & = 6.0 \\ \dot{y} \text{ for } x=11 & = 6.6 \\ \dot{y} \text{ for } x=13 & = 7.3 \\ \dot{y} \text{ for } x=15 & = 8.0 \\ \end{aligned} \][/tex]
We can find the residuals by subtracting the predicted [tex]\( \dot{y} \)[/tex] from the observed [tex]\( y \)[/tex]:
[tex]\[ \begin{aligned} \text{Residual for } x=5 & : 5 - 4.6 = 0.4 \\ \text{Residual for } x=7 & : 3 - 5.3 = -2.3 \\ \text{Residual for } x=9 & : 9 - 6.0 = 3.0 \\ \text{Residual for } x=11 & : 7 - 6.6 = 0.4 \\ \text{Residual for } x=13 & : 5 - 7.3 = -2.3 \\ \text{Residual for } x=15 & : 9 - 8.0 = 1.0 \\ \end{aligned} \][/tex]
Now, listing these residuals:
[tex]\[ [0.4, -2.3, 3.0, 0.4, -2.3, 1.0] \][/tex]
### Sum of the Residuals
The sum of the residuals is calculated by summing up all the individual residuals:
[tex]\[ 0.4 + (-2.3) + 3.0 + 0.4 + (-2.3) + 1.0 = 0.2 \][/tex]
Thus, the sum of the residuals is [tex]\( 0.2 \)[/tex].
We greatly appreciate every question and answer you provide. Keep engaging and finding the best solutions. This community is the perfect place to learn and grow together. IDNLearn.com has the solutions you’re looking for. Thanks for visiting, and see you next time for more reliable information.