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Let's walk through how we find the residuals and calculate their sum.
### Step Two: Find the Residuals
Residuals are the differences between the observed [tex]\( y \)[/tex]-values and the predicted [tex]\( \dot{y} \)[/tex]-values using the regression line [tex]\( y = 2.9 + 0.34x \)[/tex].
Given the data:
[tex]\[ \{(5,5),(7,3),(9,9),(11,7),(13,5),(15,9)\} \][/tex]
And the predicted [tex]\( \dot{y} \)[/tex] values calculated using the regression line:
[tex]\[ \begin{aligned} \dot{y} \text{ for } x=5 & = 4.6 \\ \dot{y} \text{ for } x=7 & = 5.3 \\ \dot{y} \text{ for } x=9 & = 6.0 \\ \dot{y} \text{ for } x=11 & = 6.6 \\ \dot{y} \text{ for } x=13 & = 7.3 \\ \dot{y} \text{ for } x=15 & = 8.0 \\ \end{aligned} \][/tex]
We can find the residuals by subtracting the predicted [tex]\( \dot{y} \)[/tex] from the observed [tex]\( y \)[/tex]:
[tex]\[ \begin{aligned} \text{Residual for } x=5 & : 5 - 4.6 = 0.4 \\ \text{Residual for } x=7 & : 3 - 5.3 = -2.3 \\ \text{Residual for } x=9 & : 9 - 6.0 = 3.0 \\ \text{Residual for } x=11 & : 7 - 6.6 = 0.4 \\ \text{Residual for } x=13 & : 5 - 7.3 = -2.3 \\ \text{Residual for } x=15 & : 9 - 8.0 = 1.0 \\ \end{aligned} \][/tex]
Now, listing these residuals:
[tex]\[ [0.4, -2.3, 3.0, 0.4, -2.3, 1.0] \][/tex]
### Sum of the Residuals
The sum of the residuals is calculated by summing up all the individual residuals:
[tex]\[ 0.4 + (-2.3) + 3.0 + 0.4 + (-2.3) + 1.0 = 0.2 \][/tex]
Thus, the sum of the residuals is [tex]\( 0.2 \)[/tex].
### Step Two: Find the Residuals
Residuals are the differences between the observed [tex]\( y \)[/tex]-values and the predicted [tex]\( \dot{y} \)[/tex]-values using the regression line [tex]\( y = 2.9 + 0.34x \)[/tex].
Given the data:
[tex]\[ \{(5,5),(7,3),(9,9),(11,7),(13,5),(15,9)\} \][/tex]
And the predicted [tex]\( \dot{y} \)[/tex] values calculated using the regression line:
[tex]\[ \begin{aligned} \dot{y} \text{ for } x=5 & = 4.6 \\ \dot{y} \text{ for } x=7 & = 5.3 \\ \dot{y} \text{ for } x=9 & = 6.0 \\ \dot{y} \text{ for } x=11 & = 6.6 \\ \dot{y} \text{ for } x=13 & = 7.3 \\ \dot{y} \text{ for } x=15 & = 8.0 \\ \end{aligned} \][/tex]
We can find the residuals by subtracting the predicted [tex]\( \dot{y} \)[/tex] from the observed [tex]\( y \)[/tex]:
[tex]\[ \begin{aligned} \text{Residual for } x=5 & : 5 - 4.6 = 0.4 \\ \text{Residual for } x=7 & : 3 - 5.3 = -2.3 \\ \text{Residual for } x=9 & : 9 - 6.0 = 3.0 \\ \text{Residual for } x=11 & : 7 - 6.6 = 0.4 \\ \text{Residual for } x=13 & : 5 - 7.3 = -2.3 \\ \text{Residual for } x=15 & : 9 - 8.0 = 1.0 \\ \end{aligned} \][/tex]
Now, listing these residuals:
[tex]\[ [0.4, -2.3, 3.0, 0.4, -2.3, 1.0] \][/tex]
### Sum of the Residuals
The sum of the residuals is calculated by summing up all the individual residuals:
[tex]\[ 0.4 + (-2.3) + 3.0 + 0.4 + (-2.3) + 1.0 = 0.2 \][/tex]
Thus, the sum of the residuals is [tex]\( 0.2 \)[/tex].
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