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Sagot :
Sure, let's break down the solution step-by-step and create the complete table as needed.
### Step-by-Step Solution:
1. Initial Value of the Car (Time = 0 years):
The car's initial value is \[tex]$32,000 or 32 (thousands). 2. Value After 1 Year: Each year, the car retains \( 85\% \) of its previous year's value. To find the value after 1 year, multiply the initial value by 0.85. \[ 32 \times 0.85 = 27.2 \] 3. Value After 2 Years: To find the car's value after 2 years, multiply the value after 1 year by 0.85. \[ 27.2 \times 0.85 = 23.12 \] 4. Value After 3 Years: To find the car's value after 3 years, multiply the value after 2 years by 0.85. \[ 23.12 \times 0.85 = 19.652 \] ### Summary Table: Here is the completed table showing the car's value at the start and for each year up to 3 years. \begin{tabular}{|c|c|} \hline \textbf{Time (Years)} & \textbf{Value (Thousands)} \\ \hline 0 & 32.0 \\ \hline 1 & 27.2 \\ \hline 2 & 23.12 \\ \hline 3 & 19.652 \\ \hline \end{tabular} So, the car's value declines over the years as follows: \$[/tex]32,000 at the start, \[tex]$27,200 after 1 year, \$[/tex]23,120 after 2 years, and \$19,652 after 3 years.
Note: In practice, values in financial calculations are often rounded to two decimal places. The slight variations you see (such as 23.119999999999997 instead of 23.12) are results of floating-point arithmetic precision limits in computing.
### Step-by-Step Solution:
1. Initial Value of the Car (Time = 0 years):
The car's initial value is \[tex]$32,000 or 32 (thousands). 2. Value After 1 Year: Each year, the car retains \( 85\% \) of its previous year's value. To find the value after 1 year, multiply the initial value by 0.85. \[ 32 \times 0.85 = 27.2 \] 3. Value After 2 Years: To find the car's value after 2 years, multiply the value after 1 year by 0.85. \[ 27.2 \times 0.85 = 23.12 \] 4. Value After 3 Years: To find the car's value after 3 years, multiply the value after 2 years by 0.85. \[ 23.12 \times 0.85 = 19.652 \] ### Summary Table: Here is the completed table showing the car's value at the start and for each year up to 3 years. \begin{tabular}{|c|c|} \hline \textbf{Time (Years)} & \textbf{Value (Thousands)} \\ \hline 0 & 32.0 \\ \hline 1 & 27.2 \\ \hline 2 & 23.12 \\ \hline 3 & 19.652 \\ \hline \end{tabular} So, the car's value declines over the years as follows: \$[/tex]32,000 at the start, \[tex]$27,200 after 1 year, \$[/tex]23,120 after 2 years, and \$19,652 after 3 years.
Note: In practice, values in financial calculations are often rounded to two decimal places. The slight variations you see (such as 23.119999999999997 instead of 23.12) are results of floating-point arithmetic precision limits in computing.
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