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Mathematical Reasoning

A scientist is studying red maple tree growth in a state park. She measured the trunk diameters of a sample of trees in the same month every other year. The tables show the data for two of the trees.

Tree 1:
\begin{tabular}{|r|c|}
\hline Year & \begin{tabular}{c}
Trunk \\
Diameter \\
(inches)
\end{tabular} \\
\hline 1 & 18.6 \\
\hline 3 & 19.2 \\
\hline 5 & 19.8 \\
\hline 7 & 20.4 \\
\hline 9 & 21.0 \\
\hline 11 & 21.6 \\
\hline 13 & 22.2 \\
\hline
\end{tabular}

Tree 2:
\begin{tabular}{|r|c|}
\hline Year & \begin{tabular}{c}
Trunk \\
Diameter \\
(inches)
\end{tabular} \\
\hline 1 & 11.4 \\
\hline 3 & 12.0 \\
\hline 5 & 12.6 \\
\hline 7 & 13.2 \\
\hline 9 & 13.8 \\
\hline 11 & 14.4 \\
\hline 13 & 15.0 \\
\hline
\end{tabular}

In year 13, the scientist will put tree wrap around Tree 1 to protect it from the winter snow. The height of the tree wrap needs to be 45 inches.

The wrap is priced by the square foot. To the nearest square foot, how many square feet of wrap does she need?

A. 22

B. 44

C. 121


Sagot :

To determine the number of square feet of tree wrap required for tree 1, we'll break down the calculation into the following steps:

1. Determine the diameter and circumference of tree 1 in year 13.
- The diameter of tree 1 in year 13 is given as 22.2 inches.
- To find the circumference ([tex]\( C \)[/tex]), we use the formula for the circumference of a circle: [tex]\( C = \pi \times D \)[/tex], where [tex]\( D \)[/tex] is the diameter. Thus,
[tex]\[ C = \pi \times 22.2 \approx 69.7433569096934 \text{ inches} \][/tex]

2. Calculate the area of the tree wrap in square inches.
- The height of the tree wrap is given as 45 inches.
- To find the area of the wrap ([tex]\( A \)[/tex]), we use the formula for the area of a rectangle: [tex]\( A = C \times H \)[/tex], where [tex]\( H \)[/tex] is the height. Thus,
[tex]\[ A = 69.7433569096934 \times 45 \approx 3138.4510609362032 \text{ square inches} \][/tex]

3. Convert the area from square inches to square feet.
- There are 144 square inches in 1 square foot.
- So, the area in square feet ([tex]\( A_{\text{ft}} \)[/tex]) is found by dividing the area in square inches by 144:
[tex]\[ A_{\text{ft}} = \frac{3138.4510609362032}{144} \approx 21.79479903427919 \text{ square feet} \][/tex]

4. Round the area to the nearest whole number.
- Rounding 21.79479903427919 to the nearest whole number gives us 22 square feet.

So, the number of square feet of wrap needed is:

22 square feet.

Therefore, the correct answer is:
A. 22
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