Discover a wealth of knowledge and get your questions answered on IDNLearn.com. Our experts are ready to provide in-depth answers and practical solutions to any questions you may have.
Sagot :
Let's solve the problem step-by-step.
1. Understanding the Given Dimensions:
- The outer cylinder has a diameter of 20 millimeters and a height of 21 millimeters.
- The hole inside the cylinder has a radius of 6 millimeters.
2. Calculate the Radius of the Outer Cylinder:
- The radius of the outer cylinder is half of the diameter.
[tex]\[ \text{Radius of the outer cylinder} = \frac{20}{2} = 10 \text{ millimeters} \][/tex]
3. Volume of the Outer Cylinder:
- The volume [tex]\( V \)[/tex] of a cylinder is given by the formula:
[tex]\[ V = \pi r^2 h \][/tex]
- Applying this formula to the outer cylinder:
[tex]\[ \text{Volume of the outer cylinder} = \pi (10)^2 (21) \][/tex]
[tex]\[ = 2100 \pi \text{ cubic millimeters} \][/tex]
4. Volume of the Cylindrical Hole:
- The volume of the hole, which is also cylindrical, can be computed using the same formula:
[tex]\[ V = \pi r^2 h \][/tex]
- Applying this formula to the hole:
[tex]\[ \text{Volume of the hole} = \pi (6)^2 (21) \][/tex]
[tex]\[ = 756 \pi \text{ cubic millimeters} \][/tex]
5. Volume of Metal Needed:
- The volume of metal needed to make the pipe is the volume of the outer cylinder minus the volume of the hole:
[tex]\[ \text{Volume of metal needed} = 2100 \pi - 756 \pi \][/tex]
[tex]\[ = 2100 \pi - 756 \pi \][/tex]
[tex]\[ = 1344 \pi \text{ cubic millimeters} \][/tex]
From these calculations, we can identify the correct expressions representing the volume of metal needed:
1. [tex]\( 21 \pi (10)^2 - 21 \pi (6)^2 \)[/tex]
2. [tex]\( 2100 \pi - 756 \pi \)[/tex]
Both of these expressions are accurate formulations for the volume of metal required to make the pipe.
1. Understanding the Given Dimensions:
- The outer cylinder has a diameter of 20 millimeters and a height of 21 millimeters.
- The hole inside the cylinder has a radius of 6 millimeters.
2. Calculate the Radius of the Outer Cylinder:
- The radius of the outer cylinder is half of the diameter.
[tex]\[ \text{Radius of the outer cylinder} = \frac{20}{2} = 10 \text{ millimeters} \][/tex]
3. Volume of the Outer Cylinder:
- The volume [tex]\( V \)[/tex] of a cylinder is given by the formula:
[tex]\[ V = \pi r^2 h \][/tex]
- Applying this formula to the outer cylinder:
[tex]\[ \text{Volume of the outer cylinder} = \pi (10)^2 (21) \][/tex]
[tex]\[ = 2100 \pi \text{ cubic millimeters} \][/tex]
4. Volume of the Cylindrical Hole:
- The volume of the hole, which is also cylindrical, can be computed using the same formula:
[tex]\[ V = \pi r^2 h \][/tex]
- Applying this formula to the hole:
[tex]\[ \text{Volume of the hole} = \pi (6)^2 (21) \][/tex]
[tex]\[ = 756 \pi \text{ cubic millimeters} \][/tex]
5. Volume of Metal Needed:
- The volume of metal needed to make the pipe is the volume of the outer cylinder minus the volume of the hole:
[tex]\[ \text{Volume of metal needed} = 2100 \pi - 756 \pi \][/tex]
[tex]\[ = 2100 \pi - 756 \pi \][/tex]
[tex]\[ = 1344 \pi \text{ cubic millimeters} \][/tex]
From these calculations, we can identify the correct expressions representing the volume of metal needed:
1. [tex]\( 21 \pi (10)^2 - 21 \pi (6)^2 \)[/tex]
2. [tex]\( 2100 \pi - 756 \pi \)[/tex]
Both of these expressions are accurate formulations for the volume of metal required to make the pipe.
We value your presence here. Keep sharing knowledge and helping others find the answers they need. This community is the perfect place to learn together. For dependable answers, trust IDNLearn.com. Thank you for visiting, and we look forward to helping you again soon.