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Sagot :
Certainly! Let's tackle the given expression step-by-step.
Given expression:
[tex]$4ck^2 + 10k^2 - 16ck - 40k$[/tex]
### Part A: Factoring out the Greatest Common Factor (GCF)
1. Identify the GCF:
- Look at all the terms: [tex]\(4ck^2\)[/tex], [tex]\(10k^2\)[/tex], [tex]\(-16ck\)[/tex], and [tex]\(-40k\)[/tex].
- First, find the GCF of the numerical coefficients: 4, 10, 16, and 40.
- The GCF of 4, 10, 16, and 40 is 2.
- Next, look at the variables: [tex]\(k^2\)[/tex], [tex]\(k^2\)[/tex], [tex]\(k\)[/tex], and [tex]\(k\)[/tex].
- The GCF for the variables is [tex]\(k\)[/tex] since each term has at least one [tex]\(k\)[/tex].
Combining both, the GCF is [tex]\(2k\)[/tex].
2. Factor out the GCF:
- Divide each term by [tex]\(2k\)[/tex] and factor it out.
[tex]\[ 4ck^2 + 10k^2 - 16ck - 40k = 2k(2ck + 5k - 8c - 20) \][/tex]
So, the expression factored by factoring out the greatest common factor is:
[tex]\[ 2k(2ck + 5k - 8c - 20) \][/tex]
### Part B: Factoring the Entire Expression Completely
1. Look inside the parentheses:
- The expression inside the parentheses is [tex]\(2ck + 5k - 8c - 20\)[/tex].
2. Analyze for further factorization:
- To factor this further, we look for any possible grouping or patterns.
- Review the terms [tex]\(2ck + 5k - 8c - 20\)[/tex]:
Group the terms to see if we can factor by grouping:
[tex]\[ (2ck + 5k) + (-8c - 20) \][/tex]
Factor by grouping:
[tex]\[ k(2c + 5) - 4(2c + 5) \][/tex]
Notice that both groups now include the common term [tex]\((2c + 5)\)[/tex]:
[tex]\[ k(2c + 5) - 4(2c + 5) = (k - 4)(2c + 5) \][/tex]
3. Combine with the GCF factored out:
- Replace the original factored form with this additional factorization:
[tex]\[ 2k(2ck + 5k - 8c - 20) = 2k((k - 4)(2c + 5)) \][/tex]
However, we must keep in mind that the expression we've focused on does not factor nicely into a simpler or more conventional polynomial product form. For most intents and purposes and given the simplification context, we can keep the result from the grouping:
The complete factorization is:
[tex]\[ 2k(2ck + 5k - 8c - 20) \][/tex]
To summarize:
- Part A: The expression with the GCF factored out:
[tex]\[ 2k(2ck + 5k - 8c - 20) \][/tex]
- Part B: The entire expression factored completely:
[tex]\[ 2k(2ck + 5k - 8c - 20) \][/tex]
Given expression:
[tex]$4ck^2 + 10k^2 - 16ck - 40k$[/tex]
### Part A: Factoring out the Greatest Common Factor (GCF)
1. Identify the GCF:
- Look at all the terms: [tex]\(4ck^2\)[/tex], [tex]\(10k^2\)[/tex], [tex]\(-16ck\)[/tex], and [tex]\(-40k\)[/tex].
- First, find the GCF of the numerical coefficients: 4, 10, 16, and 40.
- The GCF of 4, 10, 16, and 40 is 2.
- Next, look at the variables: [tex]\(k^2\)[/tex], [tex]\(k^2\)[/tex], [tex]\(k\)[/tex], and [tex]\(k\)[/tex].
- The GCF for the variables is [tex]\(k\)[/tex] since each term has at least one [tex]\(k\)[/tex].
Combining both, the GCF is [tex]\(2k\)[/tex].
2. Factor out the GCF:
- Divide each term by [tex]\(2k\)[/tex] and factor it out.
[tex]\[ 4ck^2 + 10k^2 - 16ck - 40k = 2k(2ck + 5k - 8c - 20) \][/tex]
So, the expression factored by factoring out the greatest common factor is:
[tex]\[ 2k(2ck + 5k - 8c - 20) \][/tex]
### Part B: Factoring the Entire Expression Completely
1. Look inside the parentheses:
- The expression inside the parentheses is [tex]\(2ck + 5k - 8c - 20\)[/tex].
2. Analyze for further factorization:
- To factor this further, we look for any possible grouping or patterns.
- Review the terms [tex]\(2ck + 5k - 8c - 20\)[/tex]:
Group the terms to see if we can factor by grouping:
[tex]\[ (2ck + 5k) + (-8c - 20) \][/tex]
Factor by grouping:
[tex]\[ k(2c + 5) - 4(2c + 5) \][/tex]
Notice that both groups now include the common term [tex]\((2c + 5)\)[/tex]:
[tex]\[ k(2c + 5) - 4(2c + 5) = (k - 4)(2c + 5) \][/tex]
3. Combine with the GCF factored out:
- Replace the original factored form with this additional factorization:
[tex]\[ 2k(2ck + 5k - 8c - 20) = 2k((k - 4)(2c + 5)) \][/tex]
However, we must keep in mind that the expression we've focused on does not factor nicely into a simpler or more conventional polynomial product form. For most intents and purposes and given the simplification context, we can keep the result from the grouping:
The complete factorization is:
[tex]\[ 2k(2ck + 5k - 8c - 20) \][/tex]
To summarize:
- Part A: The expression with the GCF factored out:
[tex]\[ 2k(2ck + 5k - 8c - 20) \][/tex]
- Part B: The entire expression factored completely:
[tex]\[ 2k(2ck + 5k - 8c - 20) \][/tex]
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