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If the frequency of an FM wave is [tex]8.85 \times 10^7[/tex] hertz, what is the period of the FM wave?

A. [tex]2.58 \times 10^{-8}[/tex] seconds
B. [tex]1.13 \times 10^{-8}[/tex] seconds
C. [tex]1.25 \times 10^{-7}[/tex] seconds
D. [tex]5.82 \times 10^{-7}[/tex] seconds


Sagot :

To find the period of a wave when given its frequency, we use the relationship between frequency (f) and period (T). The period is the reciprocal of the frequency, which is mathematically expressed as:

[tex]\[ T = \frac{1}{f} \][/tex]

Given:
[tex]\[ f = 8.85 \times 10^7 \text{ hertz} \][/tex]

We substitute the value of the frequency into the equation:

[tex]\[ T = \frac{1}{8.85 \times 10^7} \text{ seconds} \][/tex]

Upon calculating this, the period [tex]\( T \)[/tex] is found to be:

[tex]\[ T \approx 1.13 \times 10^{-8} \text{ seconds} \][/tex]

Therefore, the correct answer is:

B. [tex]\( 1.13 \times 10^{-8} \)[/tex] seconds