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Evaluate [tex]\cos \left(\sin^{-1} 0\right)[/tex].

Answer here:


Sagot :

To evaluate [tex]\(\cos \left(\operatorname{Sin}^{-1} 0\right)\)[/tex], let's break the problem into clear steps:

### Step-by-Step Solution:

1. Identify the Argument:
We need to first understand what [tex]\(\operatorname{Sin}^{-1} 0\)[/tex] (the inverse sine, or arcsine, of 0) means.

2. Evaluate [tex]\(\operatorname{Sin}^{-1} 0\)[/tex]:
By definition, [tex]\(\operatorname{Sin}^{-1} x\)[/tex] is the angle whose sine is [tex]\(x\)[/tex]. Hence, [tex]\(\operatorname{Sin}^{-1} 0\)[/tex] is the angle [tex]\(\theta\)[/tex] such that [tex]\(\sin \theta = 0\)[/tex].

- The sine function is 0 at angles like [tex]\(0, \pi, 2\pi, -\pi, -2\pi\)[/tex], etc.
- However, the principal value range for [tex]\(\operatorname{Sin}^{-1} x\)[/tex] is [tex]\([- \frac{\pi}{2}, \frac{\pi}{2}]\)[/tex]. Within this range, the angle [tex]\(\theta\)[/tex] such that [tex]\(\sin \theta = 0\)[/tex] is [tex]\(\theta = 0\)[/tex].

Hence, [tex]\(\operatorname{Sin}^{-1} 0 = 0\)[/tex].

3. Calculate the Cosine:
Now, we need to evaluate [tex]\(\cos (0)\)[/tex].

- Recall that the cosine function of 0 radians is 1, as [tex]\(\cos(0) = 1\)[/tex].

### Conclusion:

Therefore, [tex]\(\cos \left(\operatorname{Sin}^{-1} 0\right) = \cos(0) = 1\)[/tex].

The final result is:
[tex]\[ \cos \left(\operatorname{Sin}^{-1} 0\right) = 1.0 \][/tex]
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