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A recent poll of 1001 Americans aged 18 and over, conducted in May of 2013, found that 80% of the respondents "strongly agree" that K-12 schools should teach critical thinking to children.

1. What is the sample size?

2. For this survey, the margin of error is measured to be 3.2%. What is the 95% confidence interval using only one decimal place?
(Example answer: 32.6 to 42.9)


Sagot :

To determine the sample size and the 95% confidence interval for the proportion of respondents who "strongly agree" that K-12 schools should teach critical thinking to children, follow these steps:

1. Identify the sample size.
- The poll was conducted with a sample size of 1001 Americans age 18 and over.

Therefore, the sample size is 1001.

2. Look at the given proportion and margin of error.
- The proportion of respondents who "strongly agree" is 80%, or 0.80 when expressed as a decimal.
- The margin of error for this survey is 3.2%, or 0.032 when expressed as a decimal.

3. Calculate the lower and upper bounds of the confidence interval.
- The lower bound is calculated by subtracting the margin of error from the proportion:
[tex]\[ \text{Lower Bound} = 0.80 - 0.032 = 0.768 \][/tex]

- The upper bound is calculated by adding the margin of error to the proportion:
[tex]\[ \text{Upper Bound} = 0.80 + 0.032 = 0.832 \][/tex]

4. Convert these bounds to percentages and round to one decimal place:
- Lower Bound as a percentage:
[tex]\[ 0.768 \times 100 = 76.8\% \][/tex]

- Upper Bound as a percentage:
[tex]\[ 0.832 \times 100 = 83.2\% \][/tex]

So the 95% confidence interval is from 76.8% to 83.2%.

Therefore, the results summarize as follows:
- Sample size: 1001
- 95% Confidence Interval: 76.8% to 83.2%