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Solve for [tex]\( x \)[/tex]:
[tex]\[ \cos x \tan x - \cos x = 0 \][/tex]

A. [tex]\( x = \frac{\pi}{2} + n \pi, \frac{5\pi}{4} + 2n \pi \)[/tex]

B. [tex]\( x = \frac{\pi}{2} + n \pi, \frac{\pi}{4} + 2n \pi \)[/tex]

C. [tex]\( x = 0 + n \pi, \frac{5\pi}{4} + 2n \pi \)[/tex]

D. [tex]\( x = 0 + n \pi, \frac{\pi}{4} + 2n \pi \)[/tex]


Sagot :

To solve the trigonometric equation [tex]\(\cos(x) \tan(x) - \cos(x) = 0\)[/tex], let's go through a step-by-step approach.

### Step 1: Simplify the Equation

First, look at the given equation:

[tex]\[ \cos(x) \tan(x) - \cos(x) = 0 \][/tex]

We can factor out [tex]\(\cos(x)\)[/tex] from the left-hand side:

[tex]\[ \cos(x) (\tan(x) - 1) = 0 \][/tex]

This gives us two possible solutions:

1. [tex]\(\cos(x) = 0\)[/tex]
2. [tex]\(\tan(x) - 1 = 0\)[/tex]

### Step 2: Solve [tex]\(\cos(x) = 0\)[/tex]

For [tex]\(\cos(x) = 0\)[/tex], we need to find the values of [tex]\(x\)[/tex]:

[tex]\[ \cos(x) = 0 \][/tex]

The solutions are:

[tex]\[ x = \frac{\pi}{2} + n\pi \quad \text{where } n \in \mathbb{Z} \][/tex]

### Step 3: Solve [tex]\(\tan(x) - 1 = 0\)[/tex]

Next, solve the equation [tex]\(\tan(x) - 1 = 0\)[/tex], which simplifies to:

[tex]\[ \tan(x) = 1 \][/tex]

The solutions to [tex]\(\tan(x) = 1\)[/tex] are:

[tex]\[ x = \frac{\pi}{4} + n\pi \quad \text{where } n \in \mathbb{Z} \][/tex]

### Step 4: Combine the Solutions

We have two sets of solutions from the two cases:
1. [tex]\(x = \frac{\pi}{2} + n\pi\)[/tex]
2. [tex]\(x = \frac{\pi}{4} + n\pi\)[/tex]

Given these, the solution to the equation [tex]\(\cos(x)\tan(x) - \cos(x) = 0\)[/tex] can be combined and simplified. Recognizing that [tex]\(x = \frac{\pi}{4}\)[/tex] is a specific solution consistent with one set of the general solutions.

The final consistent and simplified solution for the given equation is:
[tex]\[ x = \frac{\pi}{4} + n\pi \quad \text{where } n \in \mathbb{Z} \][/tex]

Thus, the complete solution to the equation [tex]\(\cos(x) \tan(x) - \cos(x) = 0\)[/tex] is:

[tex]\[ x = \frac{\pi}{4} + 2n\pi \quad \text{for all } n \in \mathbb{Z} \][/tex]