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Part 1: Enthalpy of Baking Soda and Vinegar Reaction

Table 8.1

\begin{tabular}{|l|l|}
\hline
Volume of vinegar & 25 mL \\
\hline
Mass of sodium bicarbonate & 1 g \\
\hline
Initial temperature of vinegar & [tex]$17^{\circ} C$[/tex] \\
\hline
Final temperature of vinegar & [tex]$14^{\circ} C$[/tex] \\
\hline
Change in temperature [tex]$(\Delta T)^{\circ} C$[/tex] & \\
\hline
\end{tabular}

Sagot :

GinnyAnsweridn
Let's calculate the change in temperature (ΔT) for the given data.

1. Initial temperature of vinegar: [tex]\( 17^{\circ} C \)[/tex]

2. Final temperature of vinegar: [tex]\( 14^{\circ} C \)[/tex]

To find the change in temperature (ΔT), we use the formula:
[tex]\[ \Delta T = \text{Final Temperature} - \text{Initial Temperature} \][/tex]

Plugging in the given values:
[tex]\[ \Delta T = 14^{\circ} C - 17^{\circ} C \][/tex]

[tex]\[ \Delta T = -3^{\circ} C \][/tex]

So, the change in temperature [tex]\( \Delta T \)[/tex] is [tex]\( -3^{\circ} C \)[/tex].

Here is the completed table:

[tex]\[ \begin{tabular}{|l|l|} \hline Volume of vinegar & 25 mL \\ \hline Mass of sodium bicarbonate & 1 g \\ \hline Initial temperature of vinegar & \( 17^{\circ} C \) \\ \hline Final temperature of vinegar & \( 14^{\circ} C \) \\ \hline Change in temperature \( °C (\Delta T) \) & -3 \\ \hline \end{tabular} \][/tex]
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