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Sagot :
Answer:
D. 9800 J
Explanation:
We can find the amount of work done by lifting a 500 kg weight to a height of 2 meters by using the work formula:
[tex]\boxed{W=Fs}[/tex]
where:
- [tex]W=\texttt{work}[/tex]
- [tex]F=\texttt{applied force}[/tex]
- [tex]s=\texttt{distance}[/tex]
In this question, the applied force is equivalent to the weight, which:
[tex]\boxed{w=mg}[/tex]
where:
- [tex]w=\texttt{weight}[/tex]
- [tex]m=\texttt{mass}[/tex]
- [tex]g=\texttt{gravity}[/tex]
If we combined the 2 formulas, it will become:
[tex]\boxed{Work(W)=mgs}[/tex]
Given:
- [tex]m=500\ kg[/tex]
- [tex]s=2\ m[/tex]
- [tex]g=9.8\ m/s^2[/tex]
Then:
[tex]\begin{aligned}W&=mgs\\&=500\times2\times9.8\\&=\bf 9800\ J\end{aligned}[/tex]
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