Find solutions to your problems with the help of IDNLearn.com's knowledgeable users. Our platform is designed to provide accurate and comprehensive answers to any questions you may have.

What are the [tex]$x$[/tex]- and [tex]$y$[/tex]-coordinates of point [tex]$E$[/tex], which partitions the directed line segment from [tex]$J$[/tex] to [tex]$K$[/tex] into a ratio of [tex]$1:4$[/tex]?

[tex]\[
\begin{array}{l}
x = \left(\frac{m}{m+n}\right) \left(x_2 - x_1\right) + x_1 \\
y = \left(\frac{m}{m+n}\right) \left(y_2 - y_1\right) + y_1
\end{array}
\][/tex]

A. [tex]$(-13, -3)$[/tex]
B. [tex]$(-7, -1)$[/tex]
C. [tex]$(-5, 0)$[/tex]
D. [tex]$(17, 11)$[/tex]


Sagot :

To find the coordinates of point [tex]\( E \)[/tex], which partitions the directed line segment from [tex]\( J \)[/tex] to [tex]\( K \)[/tex] in the ratio [tex]\( 1:4 \)[/tex], we will use the section formula for internal division. The coordinates for points [tex]\( J \)[/tex] and [tex]\( K \)[/tex] are given as:

[tex]\( J(-13, -3) \)[/tex] and [tex]\( K(-7, -1) \)[/tex].

The section formula states that if a point [tex]\( E \)[/tex] divides the line segment joining two points [tex]\( J(x_1, y_1) \)[/tex] and [tex]\( K(x_2, y_2) \)[/tex] in the ratio [tex]\( m:n \)[/tex], then the coordinates of [tex]\( E \)[/tex] are given by:

[tex]\[ x = \left(\frac{m}{m+n}\right)(x_2 - x_1) + x_1 \][/tex]
[tex]\[ y = \left(\frac{m}{m+n}\right)(y_2 - y_1) + y_1 \][/tex]

Here, [tex]\( m = 1 \)[/tex] and [tex]\( n = 4 \)[/tex].
Substitute [tex]\( m = 1 \)[/tex], [tex]\( n = 4 \)[/tex], [tex]\( x_1 = -13 \)[/tex], [tex]\( y_1 = -3 \)[/tex], [tex]\( x_2 = -7 \)[/tex], and [tex]\( y_2 = -1 \)[/tex] into the formulas.

First, let's find the [tex]\( x \)[/tex]-coordinate of point [tex]\( E \)[/tex]:

[tex]\[ x = \left(\frac{1}{1+4}\right)(-7 - (-13)) + (-13) \][/tex]

Simplify the fraction and the expression inside the parentheses:

[tex]\[ x = \left(\frac{1}{5}\right)(-7 + 13) + (-13) \][/tex]
[tex]\[ x = \left(\frac{1}{5}\right)(6) + (-13) \][/tex]
[tex]\[ x = \frac{6}{5} - 13 \][/tex]

Convert [tex]\(\frac{6}{5}\)[/tex] to a decimal:

[tex]\[ \frac{6}{5} = 1.2 \][/tex]

So,

[tex]\[ x = 1.2 - 13 \][/tex]

Subtract and get the result for [tex]\( x \)[/tex]:

[tex]\[ x = 1.2 - 13 = -11.8 \][/tex]

Now, let's find the [tex]\( y \)[/tex]-coordinate of point [tex]\( E \)[/tex]:

[tex]\[ y = \left(\frac{1}{1+4}\right)(-1 - (-3)) + (-3) \][/tex]

Simplify the fraction and the expression inside the parentheses:

[tex]\[ y = \left(\frac{1}{5}\right)(-1 + 3) + (-3) \][/tex]
[tex]\[ y = \left(\frac{1}{5}\right)(2) + (-3) \][/tex]
[tex]\[ y = \frac{2}{5} - 3 \][/tex]

Convert [tex]\(\frac{2}{5}\)[/tex] to a decimal:

[tex]\[ \frac{2}{5} = 0.4 \][/tex]

So,

[tex]\[ y = 0.4 - 3 \][/tex]

Subtract and get the result for [tex]\( y \)[/tex]:

[tex]\[ y = 0.4 - 3 = -2.6 \][/tex]

Therefore, the coordinates of point [tex]\( E \)[/tex], which partitions the directed line segment from [tex]\( J \)[/tex] to [tex]\( K \)[/tex] into a ratio of [tex]\( 1:4 \)[/tex], are:

[tex]\[ (-11.8, -2.6) \][/tex]